2h₂o ⇌ h₃o⁺ + oh⁻\nchoose the conjugate acid ...
2h₂o ⇌ h₃o⁺ + oh⁻\nchoose the conjugate acid - base pairs from the above equation.\nselect all that apply\na h₂o/h₃o⁺\nb h₂o/ha\nc oh⁻/h₂o\nd a⁻/h₃o⁺
Answer
# Answer:
A. $H_2O/H_3O^{+}$, C. $OH^{-}/H_2O$
# Explanation:
## Step1: Define conjugate acid - base pair
A conjugate acid - base pair differs by one $H^{+}$.
## Step2: Analyze $H_2O/H_3O^{+}$ pair
$H_2O$ gains a $H^{+}$ to form $H_3O^{+}$, so it's a conjugate acid - base pair.
## Step3: Analyze $OH^{-}/H_2O$ pair
$OH^{-}$ gains a $H^{+}$ to form $H_2O$, so it's a conjugate acid - base pair.
## Step4: Analyze $H_2O/HA$ pair
There is no $HA$ in the given equation, not a pair.
## Step5: Analyze $A^{-}/H_3O^{+}$ pair
There is no $A^{-}$ in the given equation, not a pair.