39. complete and balance each equation. if no reaction occurs, write no reaction\na. lii(aq) + bas(aq) →
39. complete and balance each equation. if no reaction occurs, write no reaction\na. lii(aq) + bas(aq) →
Answer
Explanation:
Step1: Predict products
When $\text{LiI}(aq)$ and $\text{BaS}(aq)$ react, the cations and anions will exchange partners. The potential products are $\text{Li}{2}\text{S}$ and $\text{BaI}{2}$. The double - displacement reaction is $\text{LiI}(aq)+\text{BaS}(aq)\rightarrow\text{Li}{2}\text{S}(aq)+\text{BaI}{2}(aq)$.
Step2: Check solubility
According to solubility rules, all sulfides ($\text{S}^{2 -}$) of group 1 metals (like $\text{Li}^+$) are soluble, and all iodides ($\text{I}^-$) of metals are soluble. Since both $\text{Li}{2}\text{S}$ and $\text{BaI}{2}$ are soluble in water, no precipitate is formed.
Answer:
NO REACTION