39. rationalize the difference in boiling points for each of the following pairs of substances:\n a. n…

39. rationalize the difference in boiling points for each of the following pairs of substances:\n a. n - pentane ch3ch2ch2ch2ch3 36.2°c\n neopentane h3c - c(ch3)3 9.5°c\n b. hf 20°c\n hcl - 85°c\n c. hcl - 85°c\n licl 1360°c\n d. n - pentane ch3ch2ch2ch2ch3 36.2°c\n n - hexane ch3ch2ch2ch2ch2ch3 69°c
Answer
Explanation:
Step1: Analyze intermolecular forces in a
n - pentane has a linear structure and neopentane has a more branched structure. Linear molecules have greater surface - area contact, leading to stronger London dispersion forces. So n - pentane has a higher boiling point due to stronger London dispersion forces.
Step2: Analyze intermolecular forces in b
HF has hydrogen bonding due to the highly electronegative F atom bonded to H. HCl has only dipole - dipole forces and London dispersion forces. Hydrogen bonding is stronger than dipole - dipole and London dispersion forces, so HF has a higher boiling point.
Step3: Analyze intermolecular forces in c
HCl is a covalent compound with relatively weak intermolecular forces (dipole - dipole and London dispersion forces). LiCl is an ionic compound. Ionic compounds have strong electrostatic forces between ions. So LiCl has a much higher boiling point.
Step4: Analyze intermolecular forces in d
Both n - pentane and n - hexane are non - polar hydrocarbons with only London dispersion forces. n - hexane has more electrons and a larger molar mass, so it has stronger London dispersion forces and a higher boiling point.
Answer:
a. n - pentane has stronger London dispersion forces due to its linear shape. b. HF has hydrogen bonding while HCl has weaker dipole - dipole and London dispersion forces. c. LiCl is ionic with strong electrostatic forces, HCl is covalent with weak intermolecular forces. d. n - hexane has stronger London dispersion forces due to more electrons and larger molar mass.