p₂o₃ + 3h₂o → 2h₃po₃\nhow many grams of diphosphorus trioxide, p₂o₃, are required to produce 12 moles of…

p₂o₃ + 3h₂o → 2h₃po₃\nhow many grams of diphosphorus trioxide, p₂o₃, are required to produce 12 moles of phosphorous acid, h₃po₃?\nmolar mass p₂o₃: 109.94 g/mol\n? g p₂o₃

p₂o₃ + 3h₂o → 2h₃po₃\nhow many grams of diphosphorus trioxide, p₂o₃, are required to produce 12 moles of phosphorous acid, h₃po₃?\nmolar mass p₂o₃: 109.94 g/mol\n? g p₂o₃

Answer

Explanation:

Step1: Determine the mole ratio

From the balanced equation (P_{2}O_{3}+3H_{2}O\rightarrow 2H_{3}PO_{3}), the mole ratio of (P_{2}O_{3}) to (H_{3}PO_{3}) is (1:2).

Step2: Calculate moles of (P_{2}O_{3})

Let (n_{P_{2}O_{3}}) be the moles of (P_{2}O_{3}). Using the mole ratio (\frac{n_{P_{2}O_{3}}}{n_{H_{3}PO_{3}}}=\frac{1}{2}). Given (n_{H_{3}PO_{3}} = 12) mol. Then (n_{P_{2}O_{3}}=\frac{1}{2}\times n_{H_{3}PO_{3}}=\frac{1}{2}\times12) mol ( = 6) mol.

Step3: Calculate mass of (P_{2}O_{3})

Use the formula (m = n\times M), where (n = 6) mol and (M = 109.94) g/mol. So (m=6) mol(\times109.94) g/mol (= 659.64) g.

Answer:

(659.64)