49 grams of sulfuric acid, h₂so₄, is dissolved in 1 liter of solution. determine the molarity (m).

Explanation:

Step1: Calculate molar mass of H₂SO₄

The molar mass of H is 1 g/mol, S is 32 g/mol, and O is 16 g/mol. For H₂SO₄, $M = 2\times1+32 + 4\times16=98$ g/mol.

Step2: Calculate moles of H₂SO₄

Use the formula $n=\frac{m}{M}$, where $m = 49$ g and $M = 98$ g/mol. So $n=\frac{49}{98}=0.5$ mol.

Step3: Calculate molarity

The formula for molarity is $M=\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume of the solution in liters. Here $n = 0.5$ mol and $V = 1$ L. So $M=\frac{0.5}{1}=0.5$ M.

Answer:

0.5