9ps\natomic number, mass number, isotopes, and stuff\n1 complete the following questions. assume all atoms…

9ps\natomic number, mass number, isotopes, and stuff\n1 complete the following questions. assume all atoms are neutral.\n $_2^4he$\n element: ____\n # protons: ____\n # neutrons: ____\n $_ {26}^{56}fe$\n element: ____\n atomic #: ____\n mass #: ____\n $_{13}^{27}al$\n element: ____\n # protons: ____\n # electrons: ____\n $_{20}^{40}ca$\n element: ____\n # protons: ____\n # neutrons: ____\n # electrons: ____\n $_{10}^{20}ne$\n element: ____\n atomic #: ____\n # electrons: ____\n atomic mass: ____\n $_6^{14}c$\n element: ____\n # protons: ____\n # electrons: ____\n # neutrons: ____\n $_9^{19}f$\n element: ____\n atomic #: ____\n mass #: ____\n # electrons: ____\n $_1^1h$\n element: ____\n atomic #: ____\n # electrons: ____\n # neutrons: ____\n $_1^2h$\n element: ____\n # protons: ____\n # electrons: ____\n # neutrons: ____\n2. write the symbol for the isotope...\n a. with 8 protons and 8 neutrons\n b. with 28 protons and 30 neutrons\n c. with atomic # 11 and mass # of 23\n d. with 92 protons and mass # 238\nhow many neutrons are in this isotope?
Answer
Explanation:
Step1: Recall atomic - related concepts
The atomic number ($Z$) is equal to the number of protons. For a neutral atom, the number of electrons is equal to the number of protons. The mass number ($A$) is the sum of the number of protons and neutrons ($A = p + n$), so the number of neutrons $n=A - p$.
Step2: Analyze $\ce{_2^4He}$
- Element: Helium
-
protons: 2 (from the sub - script)
-
neutrons: $4 - 2=2$ (mass number 4 minus proton number 2)
Step3: Analyze $\ce{_{26}^{56}Fe}$
- Element: Iron
- Atomic # (same as # protons): 26
- Mass #: 56
Step4: Analyze $\ce{_{13}^{27}Al}$
- Element: Aluminum
-
protons: 13
-
electrons: 13 (since it's neutral)
Step5: Analyze $\ce{_{20}^{40}Ca}$
- Element: Calcium
-
protons: 20
-
neutrons: $40 - 20 = 20$
-
electrons: 20
Step6: Analyze $\ce{_{10}^{20}Ne}$
- Element: Neon
- Atomic #: 10
-
electrons: 10
- Atomic mass (same as mass number here): 20
Step7: Analyze $\ce{_{6}^{14}C}$
- Element: Carbon
-
protons: 6
-
electrons: 6
-
neutrons: $14 - 6=8$
Step8: Analyze $\ce{_{9}^{19}F}$
- Element: Fluorine
- Atomic #: 9
- Mass #: 19
-
electrons: 9
Step9: Analyze $\ce{_1^1H}$
- Element: Hydrogen
- Atomic #: 1
-
electrons: 1
-
neutrons: $1 - 1 = 0$
Step10: Analyze $\ce{_1^2H}$
- Element: Hydrogen (isotope called deuterium)
-
protons: 1
-
electrons: 1
-
neutrons: $2 - 1=1$
Step11: Write isotope symbols for part 2
- a. With 8 protons and 8 neutrons, atomic number $Z = 8$ (oxygen), mass number $A=8 + 8=16$. Symbol: $\ce{_8^{16}O}$
- b. With 28 protons and 30 neutrons, atomic number $Z = 28$ (nickel), mass number $A=28+30 = 58$. Symbol: $\ce{_{28}^{58}Ni}$
- c. With atomic # 11 (sodium) and mass # 23, symbol: $\ce{_{11}^{23}Na}$
- d. With 92 protons (uranium) and mass # 238, symbol: $\ce{_{92}^{238}U}$
Answer:
$\ce{_2^4He}$:
- element: Helium
-
protons: 2
-
neutrons: 2
$\ce{_{26}^{56}Fe}$:
- element: Iron
- atomic #: 26
- mass #: 56 $\ce{_{13}^{27}Al}$:
- element: Aluminum
-
protons: 13
-
electrons: 13
$\ce{_{20}^{40}Ca}$:
- element: Calcium
-
protons: 20
-
neutrons: 20
-
electrons: 20
$\ce{_{10}^{20}Ne}$:
- element: Neon
- atomic #: 10
-
electrons: 10
- atomic mass: 20 $\ce{_{6}^{14}C}$:
- element: Carbon
-
protons: 6
-
electrons: 6
-
neutrons: 8
$\ce{_{9}^{19}F}$:
- element: Fluorine
- atomic #: 9
- mass #: 19
-
electrons: 9
$\ce{_1^1H}$:
- element: Hydrogen
- atomic #: 1
-
electrons: 1
-
neutrons: 0
$\ce{_1^2H}$:
- element: Hydrogen
-
protons: 1
-
electrons: 1
-
neutrons: 1
- a. $\ce{_8^{16}O}$
- b. $\ce{_{28}^{58}Ni}$
- c. $\ce{_{11}^{23}Na}$
- d. $\ce{_{92}^{238}U}$