acetic acid (hc₂h₃o₂) is the primary component of vinegar. it is produced along with water (h₂o) when…

acetic acid (hc₂h₃o₂) is the primary component of vinegar. it is produced along with water (h₂o) when methanol (ch₃oh) reacts with carbon dioxide (co₂) and hydrogen gas (h₂). which chemical equation accurately represents this reaction? ch₃oh (l) + co₂ (g) + h₂ (g) → hc₂h₃o₂ (l) + h₂o (l) ch₃oh (l) + 3co₂ (g) + 5h₂ (g) → 3hc₂h₃o₂ (l) + h₂o (l) 2ch₃oh (l) + co₂ (g) + 2h₂ (g) → 2hc₂h₃o₂ (l) + 2h₂o (l) 2ch₃oh (l) + 2co₂ (g) + h₂ (g) → 2hc₂h₃o₂ (l) + h₂o (l)

acetic acid (hc₂h₃o₂) is the primary component of vinegar. it is produced along with water (h₂o) when methanol (ch₃oh) reacts with carbon dioxide (co₂) and hydrogen gas (h₂). which chemical equation accurately represents this reaction? ch₃oh (l) + co₂ (g) + h₂ (g) → hc₂h₃o₂ (l) + h₂o (l) ch₃oh (l) + 3co₂ (g) + 5h₂ (g) → 3hc₂h₃o₂ (l) + h₂o (l) 2ch₃oh (l) + co₂ (g) + 2h₂ (g) → 2hc₂h₃o₂ (l) + 2h₂o (l) 2ch₃oh (l) + 2co₂ (g) + h₂ (g) → 2hc₂h₃o₂ (l) + h₂o (l)

Answer

Explanation:

Step1: Check atom - conservation

For the reaction of methanol ($CH_3OH$), carbon - dioxide ($CO_2$) and hydrogen gas ($H_2$) to produce acetic acid ($HC_2H_3O_2$) and water ($H_2O$), we need to balance the number of each type of atom on both sides of the chemical equation. Let's check the number of carbon, hydrogen and oxygen atoms for each option:

Option 1: $CH_3OH_{(l)}+CO_2_{(g)}+H_2_{(g)}\to HC_2H_3O_2_{(l)}+H_2O_{(l)}$

  • Carbon atoms: Left - hand side: $1 + 1=2$, Right - hand side: $2$.
  • Hydrogen atoms: Left - hand side: $4 + 2 = 6$, Right - hand side: $4+2 = 6$.
  • Oxygen atoms: Left - hand side: $1+2 = 3$, Right - hand side: $2 + 1=3$.

Option 2: $CH_3OH_{(l)}+3CO_2_{(g)}+5H_2_{(g)}\to3HC_2H_3O_2_{(l)}+H_2O_{(l)}$

  • Carbon atoms: Left - hand side: $1+3 = 4$, Right - hand side: $6$.
  • Hydrogen atoms: Left - hand side: $4 + 10=14$, Right - hand side: $12 + 2=14$.
  • Oxygen atoms: Left - hand side: $1+6 = 7$, Right - hand side: $6+1 = 7$. Since the number of carbon atoms is not balanced, this option is incorrect.

Option 3: $2CH_3OH_{(l)}+CO_2_{(g)}+2H_2_{(g)}\to2HC_2H_3O_2_{(l)}+2H_2O_{(l)}$

  • Carbon atoms: Left - hand side: $2+1 = 3$, Right - hand side: $4$.
  • Hydrogen atoms: Left - hand side: $8 + 4=12$, Right - hand side: $8+4 = 12$.
  • Oxygen atoms: Left - hand side: $2+2 = 4$, Right - hand side: $4 + 2=6$. Since the number of carbon and oxygen atoms is not balanced, this option is incorrect.

Option 4: $2CH_3OH_{(l)}+2CO_2_{(g)}+H_2_{(g)}\to2HC_2H_3O_2_{(l)}+H_2O_{(l)}$

  • Carbon atoms: Left - hand side: $2+2 = 4$, Right - hand side: $4$.
  • Hydrogen atoms: Left - hand side: $8+2 = 10$, Right - hand side: $8 + 2=10$.
  • Oxygen atoms: Left - hand side: $2+4 = 6$, Right - hand side: $4+1 = 5$. Since the number of oxygen atoms is not balanced, this option is incorrect.

Answer:

$CH_3OH_{(l)}+CO_2_{(g)}+H_2_{(g)}\to HC_2H_3O_2_{(l)}+H_2O_{(l)}$