an acid (x) reacts with a base (y) to produce mg₃(po₄)₂. what are x and y?\nx = h₃po₃; y = mg(oh)₂\nx =…

an acid (x) reacts with a base (y) to produce mg₃(po₄)₂. what are x and y?\nx = h₃po₃; y = mg(oh)₂\nx = h₃po₄; y = mg(oh)₂\nx = h₃po₄; y = ca(oh)₂\nx = h₃po₃; y = ca(oh)₂

an acid (x) reacts with a base (y) to produce mg₃(po₄)₂. what are x and y?\nx = h₃po₃; y = mg(oh)₂\nx = h₃po₄; y = mg(oh)₂\nx = h₃po₄; y = ca(oh)₂\nx = h₃po₃; y = ca(oh)₂

Answer

Explanation:

Step1: Analyze the product

The product is $Mg_3(PO_4)_2$. The cation in the product is $Mg^{2 + }$, which must come from the base. Bases containing magnesium are of the form $Mg(OH)_2$. So the base $Y$ is $Mg(OH)_2$.

Step2: Analyze the anion source

The anion in the product is $PO_4^{3 - }$. Phosphoric acid $H_3PO_4$ dissociates to give $PO_4^{3 - }$ ions. So the acid $X$ is $H_3PO_4$.

Answer:

$X = H_3PO_4; Y=Mg(OH)_2$ (the second option)