an acid (x) reacts with a base (y) to produce mg3(po4)2. what are x and y?\no x = h3po3; y = mg(oh)2\no x =…

an acid (x) reacts with a base (y) to produce mg3(po4)2. what are x and y?\no x = h3po3; y = mg(oh)2\no x = h3po4; y = mg(oh)2\no x = h3po4; y = ca(oh)2\no x = h3po3; y = ca(oh)2

an acid (x) reacts with a base (y) to produce mg3(po4)2. what are x and y?\no x = h3po3; y = mg(oh)2\no x = h3po4; y = mg(oh)2\no x = h3po4; y = ca(oh)2\no x = h3po3; y = ca(oh)2

Answer

Answer:

B. $X = H_3PO_4; Y = Mg(OH)_2$

Explanation:

Step1: Analyze product composition

The product is $Mg_3(PO_4)_2$, which contains magnesium ($Mg^{2 + }$) and phosphate ($PO_4^{3 - }$) ions.

Step2: Determine acid

The acid should provide the phosphate - containing anion. Phosphoric acid $H_3PO_4$ dissociates to give $PO_4^{3 - }$ ions.

Step3: Determine base

The base should provide the magnesium ion. Magnesium hydroxide $Mg(OH)_2$ dissociates to give $Mg^{2+}$ ions. When $H_3PO_4$ reacts with $Mg(OH)_2$, a neutralization reaction occurs and $Mg_3(PO_4)_2$ can be formed according to the chemical equation: $2H_3PO_4+3Mg(OH)_2 = Mg_3(PO_4)_2 + 6H_2O$.