an acid is a substance that increases the con...
an acid is a substance that increases the concentration of $h_{3}o^{+}$ ions in solution. look at the reaction below of phenol $(c_{6}h_{5}oh)$ with water:\n$c_{6}h_{5}oh(aq)+h_{2}o(l)\\longrightarrow c_{6}h_{5}o^{-}(aq)+h_{3}o^{+}(aq)$\nwhich reactant acts as an acid by contributing a $h^{+}$ ion to create $h_{3}o^{+}$ in the chemical equation?\n$\\bigcirc c_{6}h_{5}oh(aq)$\n$\\bigcirc h_{2}o(l)$\n$\\bigcirc c_{6}h_{5}o^{-}(aq)$\n$\\bigcirc h_{3}o^{+}(aq)$
Answer
# Brief Explanations:
According to the definition of an acid (a substance that increases the concentration of \(H_3O^+\) ions in solution by contributing a \(H^+\) ion), in the reaction \(C_6H_5OH(aq)+H_2O(l)\to C_6H_5O^-(aq) + H_3O^+(aq)\), \(C_6H_5OH\) donates a \(H^+\) ion (as it goes from \(C_6H_5OH\) to \(C_6H_5O^-\), losing an \(H^+\)) to \(H_2O\) (which accepts the \(H^+\) to form \(H_3O^+\)). \(H_2O\) here is acting as a base (accepting the \(H^+\)), \(C_6H_5O^-\) is a product (the conjugate base of \(C_6H_5OH\)), and \(H_3O^+\) is a product (formed by the acceptance of \(H^+\) by \(H_2O\)).
# Answer:
\(C_6H_5OH(aq)\)