the acids and bases shown right cover a range of ph values. use what you know about acids, bases, and…

the acids and bases shown right cover a range of ph values. use what you know about acids, bases, and concentration to label the test tubes, in order, from most acidic to most basic. 0.1 m naoh 0.1 m hcl distilled water 0.00001 m naoh 0.001 m naoh 0.001 m hcl 0.00001 m hcl

the acids and bases shown right cover a range of ph values. use what you know about acids, bases, and concentration to label the test tubes, in order, from most acidic to most basic. 0.1 m naoh 0.1 m hcl distilled water 0.00001 m naoh 0.001 m naoh 0.001 m hcl 0.00001 m hcl

Answer

Explanation:

Step1: Recall pH - acid - base relationship

Acids have pH < 7, bases have pH > 7, and neutral substances have pH = 7. The lower the pH of an acid, the more acidic it is, and the higher the pH of a base, the more basic it is.

Step2: Calculate pH of HCl solutions

For a strong - acid like HCl, $pH=-\log[H^+]$. For 0.1 M HCl, $[H^+]=0.1\ M$, so $pH = -\log(0.1)=1$. For 0.001 M HCl, $[H^+]=0.001\ M$, so $pH=-\log(0.001) = 3$. For 0.00001 M HCl, $[H^+]=0.00001\ M$, so $pH=-\log(0.00001)=5$.

Step3: Identify neutral substance

Distilled water is neutral with pH = 7.

Step4: Calculate pH of NaOH solutions

For a strong - base like NaOH, first find $[OH^-]$, then $pOH = -\log[OH^-]$ and $pH=14 - pOH$. For 0.1 M NaOH, $[OH^-]=0.1\ M$, $pOH=-\log(0.1) = 1$, $pH = 14 - 1=13$. For 0.001 M NaOH, $[OH^-]=0.001\ M$, $pOH=-\log(0.001)=3$, $pH = 14 - 3 = 11$. For 0.00001 M NaOH, $[OH^-]=0.00001\ M$, $pOH=-\log(0.00001)=5$, $pH=14 - 5 = 9$.

Step5: Order from most acidic to most basic

Based on the calculated pH values, the order is 0.1 M HCl, 0.001 M HCl, 0.00001 M HCl, Distilled Water, 0.00001 M NaOH, 0.001 M NaOH, 0.1 M NaOH.

Answer:

0.1 M HCl, 0.001 M HCl, 0.00001 M HCl, Distilled Water, 0.00001 M NaOH, 0.001 M NaOH, 0.1 M NaOH