which additional product balances the reaction h₂so₄ + 2naoh → na₂so₄ + ______?\n2h₂o\n2oh\nh₂o₂\nh₃o
which additional product balances the reaction h₂so₄ + 2naoh → na₂so₄ + ______?\n2h₂o\n2oh\nh₂o₂\nh₃o
Answer
Explanation:
Step1: Analyze reactant elements
The reactants are $H_2SO_4$ and $2NaOH$. The elements present are hydrogen ($H$), sulfur ($S$), oxygen ($O$) and sodium ($Na$).
Step2: Count atoms on reactant side
In $H_2SO_4$, we have 2 $H$, 1 $S$, 4 $O$. In $2NaOH$, we have 2 $Na$, 2 $O$ and 2 $H$. So in total on the reactant - side, we have 4 $H$, 1 $S$, 6 $O$ and 2 $Na$.
Step3: Analyze product side atoms
In $Na_2SO_4$, we have 2 $Na$, 1 $S$ and 4 $O$. We are missing 4 $H$ and 2 $O$.
Step4: Determine the product
Two water ($H_2O$) molecules have 4 $H$ and 2 $O$. So the balanced equation is $H_2SO_4 + 2NaOH=Na_2SO_4 + 2H_2O$.
Answer:
A. $2H_2O$