4. ammonium carbonate decomposes to produce ammonia (nh3), water and carbon dioxide. if mary has 450…

4. ammonium carbonate decomposes to produce ammonia (nh3), water and carbon dioxide. if mary has 450 milliliters of a 5 m ammonium carbonate solution, how many grams of ammonia can you predict that she would yield from this reaction?

4. ammonium carbonate decomposes to produce ammonia (nh3), water and carbon dioxide. if mary has 450 milliliters of a 5 m ammonium carbonate solution, how many grams of ammonia can you predict that she would yield from this reaction?

Answer

Explanation:

Step1: Calculate moles of ammonium carbonate

First, convert volume to liters ($V = 450\ mL=0.45\ L$) and use the formula $n = M\times V$. Given $M = 5\ mol/L$ and $V = 0.45\ L$, so $n_{(NH_4)_2CO_3}=5\ mol/L\times0.45\ L = 2.25\ mol$.

Step2: Write the decomposition reaction

The decomposition reaction of ammonium carbonate is $(NH_4)2CO_3\rightarrow2NH_3 + H_2O+CO_2$. From the stoichiometry, 1 mole of $(NH_4)2CO_3$ produces 2 moles of $NH_3$. So moles of $NH_3$ produced, $n{NH_3}=2\times n{(NH_4)_2CO_3}=2\times2.25\ mol = 4.5\ mol$.

Step3: Calculate mass of ammonia

The molar - mass of $NH_3$ is $M_{NH_3}=(14 + 3\times1)\ g/mol=17\ g/mol$. Using the formula $m = n\times M$, we get $m_{NH_3}=4.5\ mol\times17\ g/mol = 76.5\ g$.

Answer:

76.5 g