in antoine lavoisiers classic experiment, mercuric oxide is heated in a sealed container. the solid red…
in antoine lavoisiers classic experiment, mercuric oxide is heated in a sealed container. the solid red powder is changed into two products: silver liquid mercury and oxygen gas. if lavoisier heated 100 grams of powdered mercuric oxide to produce 93 grams of liquid mercury, how much oxygen would be released? a 7 grams b 16 grams c 32 grams d 93 grams
Answer
Explanation:
Step1: Apply law of conservation of mass
The mass of reactants equals the mass of products in a chemical - reaction. Here, the reactant is mercuric oxide and the products are mercury and oxygen. Let the mass of oxygen be $x$. The mass of mercuric oxide = mass of mercury+mass of oxygen. We know that the mass of mercuric oxide is 100 grams and the mass of mercury is 93 grams. So, $100 = 93 + x$.
Step2: Solve for the mass of oxygen
$x=100 - 93$. $x = 7$ grams.
Answer:
A. 7 grams