which atom (only symbol) has the electron - configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d2? blank…

which atom (only symbol) has the electron - configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d2? blank 1\nblank 1 add your answer\nquestion 12\n10 points\nwhat is the energy of light associated with a transition from n = 3 to n = 8 in a hydrogen atom? does this represent absorption or emission of a photon?\na 4.54×10 - 19j, absorption\nb 4.54×10 - 19j, emission\nc 6.81×10 - 20j, absorption\nd 2.08×10 - 19j, emission\ne 2.08×10 - 19j, absorption\nquestion 13\n10 points\nwhat mass (in g) does 7.98 moles of kr have?\nlast saved 10:02:03 pm\nquestions filter (26)

which atom (only symbol) has the electron - configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d2? blank 1\nblank 1 add your answer\nquestion 12\n10 points\nwhat is the energy of light associated with a transition from n = 3 to n = 8 in a hydrogen atom? does this represent absorption or emission of a photon?\na 4.54×10 - 19j, absorption\nb 4.54×10 - 19j, emission\nc 6.81×10 - 20j, absorption\nd 2.08×10 - 19j, emission\ne 2.08×10 - 19j, absorption\nquestion 13\n10 points\nwhat mass (in g) does 7.98 moles of kr have?\nlast saved 10:02:03 pm\nquestions filter (26)

Answer

Explanation:

Step1: Determine the atomic number from electron - configuration

The sum of electrons in the given electron - configuration (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{2}) is (2 + 2+6 + 2+6 + 2+10 + 6+2 + 2=40). The atomic number (Z) is equal to the number of electrons in a neutral atom.

Step2: Identify the element

The element with atomic number (40) is zirconium, symbol (Zr).

Step3: Calculate the energy for hydrogen - atom transition

The energy of a photon in a hydrogen - atom transition is given by the formula (E = - 2.178\times10^{-18}\text{ J}\left(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}}\right)), where (n_{i} = 3) and (n_{f}=8). [ \begin{align*} E&=- 2.178\times10^{-18}\text{ J}\left(\frac{1}{8^{2}}-\frac{1}{3^{2}}\right)\ &=- 2.178\times10^{-18}\text{ J}\left(\frac{1}{64}-\frac{1}{9}\right)\ &=- 2.178\times10^{-18}\text{ J}\left(\frac{9 - 64}{64\times9}\right)\ &=- 2.178\times10^{-18}\text{ J}\left(\frac{- 55}{576}\right)\ &=2.08\times10^{-19}\text{ J} \end{align*} ] Since the electron is moving from a lower energy level ((n = 3)) to a higher energy level ((n = 8)), this is an absorption process.

Step4: Calculate the mass of (Kr)

The molar mass of (Kr) is (M = 83.80\text{ g/mol}). Using the formula (m=nM), where (n = 7.98\text{ mol}) and (M = 83.80\text{ g/mol}), we have (m=7.98\text{ mol}\times83.80\text{ g/mol}=669\text{ g}).

Answer:

Question 11: (Zr) Question 12: E. (2.08\times 10^{-19}\text{ J}), absorption Question 13: (669\text{ g})