balance the following chemical equations.\n1. ___ sicl₄(l) + ___ h₂o(l) → ___ sio₂(s) + ___ hcl(aq)\n2. ___…

balance the following chemical equations.\n1. ___ sicl₄(l) + ___ h₂o(l) → ___ sio₂(s) + ___ hcl(aq)\n2. ___ as + ___ naoh → ___ na₃aso₃ + ___ h₂\n3. ___ au₂s₃ + ___ h₂ → ___ au + ___ h₂s\n4. ___ v₂o₅ + ___ hcl → ___ vocl₃ + ___ h₂o\n5. ___ hg(oh)₂ + ___ h₃po₄ → ___ hg₃(po₄)₂ + ___ h₂o\n6. ___ sio₂ + ___ hf → ___ sif₄ + ___ h₂o\n7. ___ zn + ___ hcl → ___ zncl₂ + ___ h₂\n8. ___ hclo₄ + ___ p₄o₁₀ → ___ h₃po₄ + ___ cl₂o₇\n9. ___ n₂(g) + ___ o₂(g) + ___ h₂o → ___ hno₃(aq)\n10. ___ nh₄no₃ → ___ n₂ + ___ o₂ + ___ h₂o

balance the following chemical equations.\n1. ___ sicl₄(l) + ___ h₂o(l) → ___ sio₂(s) + ___ hcl(aq)\n2. ___ as + ___ naoh → ___ na₃aso₃ + ___ h₂\n3. ___ au₂s₃ + ___ h₂ → ___ au + ___ h₂s\n4. ___ v₂o₅ + ___ hcl → ___ vocl₃ + ___ h₂o\n5. ___ hg(oh)₂ + ___ h₃po₄ → ___ hg₃(po₄)₂ + ___ h₂o\n6. ___ sio₂ + ___ hf → ___ sif₄ + ___ h₂o\n7. ___ zn + ___ hcl → ___ zncl₂ + ___ h₂\n8. ___ hclo₄ + ___ p₄o₁₀ → ___ h₃po₄ + ___ cl₂o₇\n9. ___ n₂(g) + ___ o₂(g) + ___ h₂o → ___ hno₃(aq)\n10. ___ nh₄no₃ → ___ n₂ + ___ o₂ + ___ h₂o

Answer

Explanation:

Step1: Balance Si in equation 1

There is 1 Si on both sides, so the coefficient of $SiCl_{4}$ and $SiO_{2}$ is 1.

Step2: Balance Cl in equation 1

Since there are 4 Cl in $SiCl_{4}$, the coefficient of HCl is 4.

Step3: Balance H and O in equation 1

There are 4 H and 2 O in 4HCl and 1 $SiO_{2}$. So the coefficient of $H_{2}O$ is 2. The balanced equation is $SiCl_{4}(l)+2H_{2}O(l)\rightarrow SiO_{2}(s) + 4HCl(aq)$.

Step4: Balance As in equation 2

Let the coefficient of As be 2, then the coefficient of $Na_{3}AsO_{3}$ is 2.

Step5: Balance Na in equation 2

Since there are 6 Na in 2$Na_{3}AsO_{3}$, the coefficient of NaOH is 6.

Step6: Balance H and O in equation 2

There are 6 H in 6NaOH. So the coefficient of $H_{2}$ is 3. The balanced equation is $2As + 6NaOH\rightarrow2Na_{3}AsO_{3}+3H_{2}$.

Step7: Balance Au in equation 3

The coefficient of $Au_{2}S_{3}$ is 1, so the coefficient of Au is 2.

Step8: Balance S in equation 3

There are 3 S in $Au_{2}S_{3}$, so the coefficient of $H_{2}S$ is 3.

Step9: Balance H in equation 3

There are 6 H in 3$H_{2}S$, so the coefficient of $H_{2}$ is 3. The balanced equation is $Au_{2}S_{3}+3H_{2}\rightarrow2Au + 3H_{2}S$.

Step10: Balance V in equation 4

The coefficient of $V_{2}O_{5}$ is 1, so the coefficient of $VOCl_{3}$ is 2.

Step11: Balance Cl in equation 4

There are 6 Cl in 2$VOCl_{3}$, so the coefficient of HCl is 6.

Step12: Balance H and O in equation 4

There are 6 H and 5 O in 6HCl and 1 $V_{2}O_{5}$. So the coefficient of $H_{2}O$ is 3. The balanced equation is $V_{2}O_{5}+6HCl\rightarrow2VOCl_{3}+3H_{2}O$.

Step13: Balance Hg in equation 5

The coefficient of $Hg(OH){2}$ is 3, then the coefficient of $Hg{3}(PO_{4})_{2}$ is 1.

Step14: Balance P in equation 5

There are 2 P in $Hg_{3}(PO_{4}){2}$, so the coefficient of $H{3}PO_{4}$ is 2.

Step15: Balance H and O in equation 5

There are 12 H and 14 O in 3$Hg(OH){2}$ and 2$H{3}PO_{4}$. So the coefficient of $H_{2}O$ is 6. The balanced equation is $3Hg(OH){2}+2H{3}PO_{4}\rightarrow Hg_{3}(PO_{4}){2}+6H{2}O$.

Step16: Balance Si in equation 6

The coefficient of $SiO_{2}$ and $SiF_{4}$ is 1.

Step17: Balance F in equation 6

There are 4 F in $SiF_{4}$, so the coefficient of HF is 4.

Step18: Balance H and O in equation 6

There are 4 H and 2 O in 4HF and 1 $SiO_{2}$. So the coefficient of $H_{2}O$ is 2. The balanced equation is $SiO_{2}+4HF\rightarrow SiF_{4}+2H_{2}O$.

Step19: Balance Zn in equation 7

The coefficient of Zn and $ZnCl_{2}$ is 1.

Step20: Balance Cl in equation 7

There are 2 Cl in $ZnCl_{2}$, so the coefficient of HCl is 2.

Step21: Balance H in equation 7

There are 2 H in 2HCl, so the coefficient of $H_{2}$ is 1. The balanced equation is $Zn + 2HCl\rightarrow ZnCl_{2}+H_{2}$.

Step22: Balance P in equation 8

The coefficient of $P_{4}O_{10}$ is 1, so the coefficient of $H_{3}PO_{4}$ is 4.

Step23: Balance Cl in equation 8

Let the coefficient of $HClO_{4}$ be 12, then the coefficient of $Cl_{2}O_{7}$ is 6.

Step24: Balance H and O in equation 8

The equation is balanced. The balanced equation is $12HClO_{4}+P_{4}O_{10}\rightarrow4H_{3}PO_{4}+6Cl_{2}O_{7}$.

Step25: Balance N in equation 9

The coefficient of $N_{2}$ is 1, so the coefficient of $HNO_{3}$ is 2.

Step26: Balance H and O in equation 9

The coefficient of $O_{2}$ is $\frac{5}{2}$ and $H_{2}O$ is 1. Multiply all coefficients by 2 to get integer - coefficients. The balanced equation is $2N_{2}(g)+5O_{2}(g)+2H_{2}O\rightarrow4HNO_{3}(aq)$.

Step27: Balance N in equation 10

The coefficient of $NH_{4}NO_{3}$ is 2, then the coefficient of $N_{2}$ is 2.

Step28: Balance O and H in equation 10

The coefficient of $O_{2}$ is 1 and $H_{2}O$ is 4. The balanced equation is $2NH_{4}NO_{3}\rightarrow2N_{2}+O_{2}+4H_{2}O$.

Answer:

  1. $1SiCl_{4}(l)+2H_{2}O(l)\rightarrow1SiO_{2}(s) + 4HCl(aq)$
  2. $2As + 6NaOH\rightarrow2Na_{3}AsO_{3}+3H_{2}$
  3. $1Au_{2}S_{3}+3H_{2}\rightarrow2Au + 3H_{2}S$
  4. $1V_{2}O_{5}+6HCl\rightarrow2VOCl_{3}+3H_{2}O$
  5. $3Hg(OH){2}+2H{3}PO_{4}\rightarrow1Hg_{3}(PO_{4}){2}+6H{2}O$
  6. $1SiO_{2}+4HF\rightarrow1SiF_{4}+2H_{2}O$
  7. $1Zn + 2HCl\rightarrow1ZnCl_{2}+1H_{2}$
  8. $12HClO_{4}+1P_{4}O_{10}\rightarrow4H_{3}PO_{4}+6Cl_{2}O_{7}$
  9. $2N_{2}(g)+5O_{2}(g)+2H_{2}O\rightarrow4HNO_{3}(aq)$
  10. $2NH_{4}NO_{3}\rightarrow2N_{2}+1O_{2}+4H_{2}O$