this balanced chemical equation demonstrates the law of conservation of mass, meaning the number of each…

this balanced chemical equation demonstrates the law of conservation of mass, meaning the number of each type of atom is equal on both sides of the equation. 6co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂. match each element with the number of atoms found in the reactants and products. c (carbon) o (oxygen) h (hydrogen)

this balanced chemical equation demonstrates the law of conservation of mass, meaning the number of each type of atom is equal on both sides of the equation. 6co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂. match each element with the number of atoms found in the reactants and products. c (carbon) o (oxygen) h (hydrogen)

Answer

Explanation:

Step1: Count carbon atoms

In reactants: $6$ in $6CO_2$. In products: $6$ in $C_6H_{12}O_6$. So, 6 carbon atoms.

Step2: Count oxygen atoms

In reactants: $6\times2$ (from $6CO_2$) + $6$ (from $6H_2O$) = $12 + 6=18$. In products: $6$ (from $C_6H_{12}O_6$) + $6\times2$ (from $6O_2$) = $6+12 = 18$. So, 18 oxygen atoms.

Step3: Count hydrogen atoms

In reactants: $6\times2$ (from $6H_2O$) = 12. In products: $12$ (from $C_6H_{12}O_6$). So, 12 hydrogen atoms.

Answer:

C (carbon): 6 O (oxygen): 18 H (hydrogen): 12