which is the balanced equation for v₂o₅ + cas → cao + v₂s₅?\nv₂o₅ + cas → cao + v₂s₅\n5v₂o₅ + 5cas → 10cao +…

Explanation:

Step1: Check element - by - element balance

For the given reaction $V_2O_5+CaS\rightarrow CaO + V_2S_5$, we need to balance the number of each type of atom on both sides of the equation.

1. Vanadium (V): In the reactants, we have 2 V atoms in $V_2O_5$ and in the products, we have 2 V atoms in $V_2S_5$. Vanadium is already balanced without adding coefficients.
2. Oxygen (O): There are 5 O atoms in $V_2O_5$ on the reactant side and 1 O atom in $CaO$ on the product side.
3. Calcium (Ca): There is 1 Ca atom in $CaS$ on the reactant side and 1 Ca atom in $CaO$ on the product side.
4. Sulfur (S): There is 1 S atom in $CaS$ on the reactant side and 5 S atoms in $V_2S_5$ on the product side.

To balance the S atoms, we need to have 5 moles of $CaS$ on the reactant side. When we have 5 moles of $CaS$, we also get 5 Ca atoms. To balance the Ca atoms on the product side, we need 5 moles of $CaO$.

The balanced chemical equation is $V_2O_5 + 5CaS\rightarrow5CaO+V_2S_5$.

Answer:

D. $V_2O_5 + 5CaS\rightarrow5CaO+V_2S_5$