which is the balanced equation for v2o5 + cas → cao + v2s5?\no v2o5 + cas → cao + v2s5\no 5v2o5 + 5cas →…

Explanation:

Step1: Check element - by - element balance

For the given reaction $V_2O_5+CaS\rightarrow CaO + V_2S_5$, we need to balance the number of each type of atom on both sides of the equation.

1. Vanadium (V): There are 2 V atoms on the left - hand side ($V_2O_5$) and 2 V atoms on the right - hand side ($V_2S_5$) in all the options, so V is already balanced without any coefficient change.
2. Oxygen (O): There are 5 O atoms in $V_2O_5$ on the left - hand side. On the right - hand side, O is in $CaO$.
3. Calcium (Ca): There is 1 Ca atom in $CaS$ on the left - hand side and 1 Ca atom in $CaO$ on the right - hand side.
4. Sulfur (S): There is 1 S atom in $CaS$ on the left - hand side and 5 S atoms in $V_2S_5$ on the right - hand side.

To balance the S atoms, we need 5 moles of $CaS$ on the left - hand side. When we have 5 moles of $CaS$, we also need 5 moles of $CaO$ on the right - hand side to balance the Ca atoms.

The balanced equation is $V_2O_5 + 5CaS\rightarrow5CaO+V_2S_5$.

Answer:

D. $V_2O_5 + 5CaS\rightarrow5CaO+V_2S_5$