balancing chemical equations\nbalance the equations below:\n1) ___ n₂ + ___ h₂ → ___ nh₃\n2) ___ kclo₃ → ___…

balancing chemical equations\nbalance the equations below:\n1) ___ n₂ + ___ h₂ → ___ nh₃\n2) ___ kclo₃ → ___ kcl + ___ o₂\n3) ___ nacl + ___ f₂ → ___ naf + ___ cl₂\n4) ___ h₂ + ___ o₂ → ___ h₂o\n5) ___ pb(oh)₂ + ___ hcl → ___ h₂o + ___ pbcl₂\n6) ___ ch₄ + ___ o₂ → ___ co₂ + ___ h₂o\n7) ___ p + ___ o₂ → ___ p₂o₅\n8) ___ ag₂o → ___ ag + ___ o₂\n9) ___ s₈ + ___ o₂ → ___ so₃\n10) ___ k + ___ mgbr₂ → ___ kbr + ___ mg

balancing chemical equations\nbalance the equations below:\n1) ___ n₂ + ___ h₂ → ___ nh₃\n2) ___ kclo₃ → ___ kcl + ___ o₂\n3) ___ nacl + ___ f₂ → ___ naf + ___ cl₂\n4) ___ h₂ + ___ o₂ → ___ h₂o\n5) ___ pb(oh)₂ + ___ hcl → ___ h₂o + ___ pbcl₂\n6) ___ ch₄ + ___ o₂ → ___ co₂ + ___ h₂o\n7) ___ p + ___ o₂ → ___ p₂o₅\n8) ___ ag₂o → ___ ag + ___ o₂\n9) ___ s₈ + ___ o₂ → ___ so₃\n10) ___ k + ___ mgbr₂ → ___ kbr + ___ mg

Answer

Explanation:

Step1: Balance nitrogen in $N_2 + H_2\rightarrow NH_3$

We have 2 nitrogen atoms on the left - hand side. To balance nitrogen, we put a 2 in front of $NH_3$. Then we balance hydrogen. We need 3 $H_2$ to get 6 hydrogen atoms on the left - hand side to match the 6 in $2NH_3$. So the balanced equation is $N_2+3H_2\rightarrow 2NH_3$.

Step2: Balance oxygen in $KClO_3\rightarrow KCl + O_2$

The least - common multiple of 3 (from $KClO_3$) and 2 (from $O_2$) for oxygen atoms is 6. So we put a 2 in front of $KClO_3$ and a 3 in front of $O_2$. Then we balance potassium and chlorine by putting a 2 in front of $KCl$. The balanced equation is $2KClO_3\rightarrow 2KCl + 3O_2$.

Step3: Balance chlorine and fluorine in $NaCl+F_2\rightarrow NaF + Cl_2$

We put a 2 in front of $NaCl$ and $NaF$ to balance sodium and chlorine. Then we have 2 fluorine atoms on the right - hand side, so we don't need to change the coefficient of $F_2$. The balanced equation is $2NaCl+F_2\rightarrow 2NaF + Cl_2$.

Step4: Balance oxygen in $H_2+O_2\rightarrow H_2O$

We put a 2 in front of $H_2O$ to balance oxygen. Then we balance hydrogen by putting a 2 in front of $H_2$. The balanced equation is $2H_2+O_2\rightarrow 2H_2O$.

Step5: Balance lead, chlorine, oxygen and hydrogen in $Pb(OH)_2+HCl\rightarrow H_2O+PbCl_2$

We put a 2 in front of $HCl$ and $H_2O$ to balance chlorine, hydrogen and oxygen. The balanced equation is $Pb(OH)_2 + 2HCl\rightarrow 2H_2O+PbCl_2$.

Step6: Balance carbon, hydrogen and oxygen in $CH_4+O_2\rightarrow CO_2+H_2O$

We first balance carbon by having 1 $CO_2$ for 1 $CH_4$. Then we balance hydrogen. Since there are 4 hydrogen atoms in $CH_4$, we put a 2 in front of $H_2O$. Then we balance oxygen. We need 2 $O_2$ to get 4 oxygen atoms on the left - hand side. The balanced equation is $CH_4+2O_2\rightarrow CO_2 + 2H_2O$.

Step7: Balance phosphorus and oxygen in $P+O_2\rightarrow P_2O_5$

The least - common multiple of 1 (from $P$) and 2 (from $P_2$) for phosphorus is 2, and for oxygen, the least - common multiple of 2 (from $O_2$) and 5 (from $P_2O_5$) is 10. We put a 4 in front of $P$ and a 5 in front of $O_2$ and a 2 in front of $P_2O_5$. The balanced equation is $4P+5O_2\rightarrow 2P_2O_5$.

Step8: Balance silver and oxygen in $Ag_2O\rightarrow Ag+O_2$

We put a 2 in front of $Ag_2O$ to balance oxygen, and then a 4 in front of $Ag$ to balance silver. The balanced equation is $2Ag_2O\rightarrow 4Ag+O_2$.

Step9: Balance sulfur and oxygen in $S_8+O_2\rightarrow SO_3$

We put an 8 in front of $SO_3$ to balance sulfur. Then we need 12 $O_2$ to get 24 oxygen atoms on the left - hand side. The balanced equation is $S_8+12O_2\rightarrow 8SO_3$.

Step10: Balance potassium, magnesium and bromine in $K+MgBr_2\rightarrow KBr+Mg$

We put a 2 in front of $K$ and $KBr$ to balance potassium and bromine. The balanced equation is $2K+MgBr_2\rightarrow 2KBr+Mg$.

Answer:

  1. $1N_2 + 3H_2\rightarrow 2NH_3$
  2. $2KClO_3\rightarrow 2KCl + 3O_2$
  3. $2NaCl+F_2\rightarrow 2NaF + Cl_2$
  4. $2H_2+O_2\rightarrow 2H_2O$
  5. $Pb(OH)_2 + 2HCl\rightarrow 2H_2O+PbCl_2$
  6. $CH_4+2O_2\rightarrow CO_2 + 2H_2O$
  7. $4P+5O_2\rightarrow 2P_2O_5$
  8. $2Ag_2O\rightarrow 4Ag+O_2$
  9. $S_8+12O_2\rightarrow 8SO_3$
  10. $2K+MgBr_2\rightarrow 2KBr+Mg$