balancing chemical equations\n1. list the steps involved in balancing a chemical equation.\n\nbalance each…

balancing chemical equations\n1. list the steps involved in balancing a chemical equation.\n\nbalance each of the chemical equations below. note that not every blank will need a coefficient\n2. __h₂ + __o₂ → __h₂o\n3. __n₂ + __h₂ → __nh₃\n4. __co₂ + __h₂0 → __c₆h₁₂o₆ + __o₂\n5. __zn + __hcl → __zncl₂ + __h₂\n6. __fe + __o₂ → __fe₂o₃\n7. __al + __feo → __al₂o₃ + __fe\n8. __p₄ + __o₂ → __p₂o₅\n9. __n₂ + __h₂ → __nh₃\n10. __al + __o₂ → __al₂o₃\n11. __p₄ + __h₂ → __ph₃\n12. __li + __o₂ → __li₂o\n13. write the balanced chemical equation for the following chemical reaction: tin oxide and hydrogen gas react to produce tin and water. (note that the chemical formula for tin oxide is sno₂ and the chemical formula for hydrogen gas is h₂.)

balancing chemical equations\n1. list the steps involved in balancing a chemical equation.\n\nbalance each of the chemical equations below. note that not every blank will need a coefficient\n2. __h₂ + __o₂ → __h₂o\n3. __n₂ + __h₂ → __nh₃\n4. __co₂ + __h₂0 → __c₆h₁₂o₆ + __o₂\n5. __zn + __hcl → __zncl₂ + __h₂\n6. __fe + __o₂ → __fe₂o₃\n7. __al + __feo → __al₂o₃ + __fe\n8. __p₄ + __o₂ → __p₂o₅\n9. __n₂ + __h₂ → __nh₃\n10. __al + __o₂ → __al₂o₃\n11. __p₄ + __h₂ → __ph₃\n12. __li + __o₂ → __li₂o\n13. write the balanced chemical equation for the following chemical reaction: tin oxide and hydrogen gas react to produce tin and water. (note that the chemical formula for tin oxide is sno₂ and the chemical formula for hydrogen gas is h₂.)

Answer

Explanation:

Step1: List steps for balancing

  1. Identify the elements in the reactants and products.
  2. Start with the most complex - looking compound.
  3. Adjust coefficients to balance the number of atoms of each element on both sides of the equation.
  4. Check the balance of all elements at the end.

Step2: Balance equation 2

For $2H_2+O_2\rightarrow2H_2O$, we have 4 hydrogen atoms and 2 oxygen atoms on both sides.

Step3: Balance equation 3

$N_2 + 3H_2\rightarrow2NH_3$. There are 2 nitrogen and 6 hydrogen atoms on both sides.

Step4: Balance equation 4

$6CO_2+6H_2O\rightarrow C_6H_{12}O_6 + 6O_2$. There are 6 carbon, 12 hydrogen and 18 oxygen atoms on both sides.

Step5: Balance equation 5

$Zn + 2HCl\rightarrow ZnCl_2+H_2$. There is 1 zinc, 2 hydrogen and 2 chlorine atoms on both sides.

Step6: Balance equation 6

$4Fe+3O_2\rightarrow2Fe_2O_3$. There are 4 iron and 6 oxygen atoms on both sides.

Step7: Balance equation 7

$2Al + 3FeO\rightarrow Al_2O_3+3Fe$. There are 2 aluminum, 3 iron and 3 oxygen atoms on both sides.

Step8: Balance equation 8

$P_4+5O_2\rightarrow2P_2O_5$. There are 4 phosphorus and 10 oxygen atoms on both sides.

Step9: Balance equation 9

Same as equation 3: $N_2 + 3H_2\rightarrow2NH_3$

Step10: Balance equation 10

$4Al+3O_2\rightarrow2Al_2O_3$. There are 4 aluminum and 6 oxygen atoms on both sides.

Step11: Balance equation 11

$P_4+6H_2\rightarrow4PH_3$. There are 4 phosphorus and 12 hydrogen atoms on both sides.

Step12: Balance equation 12

$4Li+O_2\rightarrow2Li_2O$. There are 4 lithium and 2 oxygen atoms on both sides.

Step13: Balance equation 13

$SnO_2 + 2H_2\rightarrow Sn+2H_2O$. There is 1 tin, 2 oxygen and 4 hydrogen atoms on both sides.

Answer:

  1. Steps: Identify elements, start with complex compound, adjust coefficients, check balance.
  2. $2H_2+O_2\rightarrow2H_2O$
  3. $N_2 + 3H_2\rightarrow2NH_3$
  4. $6CO_2+6H_2O\rightarrow C_6H_{12}O_6 + 6O_2$
  5. $Zn + 2HCl\rightarrow ZnCl_2+H_2$
  6. $4Fe+3O_2\rightarrow2Fe_2O_3$
  7. $2Al + 3FeO\rightarrow Al_2O_3+3Fe$
  8. $P_4+5O_2\rightarrow2P_2O_5$
  9. $N_2 + 3H_2\rightarrow2NH_3$
  10. $4Al+3O_2\rightarrow2Al_2O_3$
  11. $P_4+6H_2\rightarrow4PH_3$
  12. $4Li+O_2\rightarrow2Li_2O$
  13. $SnO_2 + 2H_2\rightarrow Sn+2H_2O$