balancing chemical equations - worksheet #1\nbalance the following chemical equations:\n1. ____al (s) +…

balancing chemical equations - worksheet #1\nbalance the following chemical equations:\n1. ____al (s) + ____hcl (aq) ____alcl3 (aq) + ____h2 (g)\n2. ____k (s) + ____h2o (l) ____koh (aq) + ____h2 (g)\n3. ____mg (s) + ____n2 (g) ____mg3n2 (s)\n4. ____nano3 (s) ____nano2 (s) + ____o2 (g)\n5. ____ca(oh)2 (s) + ____h3po4 (aq) ____ca3(po4)2 (s) + ____h2o (l)\n6. ____c3h8 (g) + ____o2 (g) ____co2 (g) + ____h2o (g)\n7. ____nh3 (g) + ____o2 (g) ____no (g) + ____h2 (g)\n8. ____n2 (g) + ____h2 (g) ____nh3 (g)\n9. ____na2co3 (s) + ____hcl (aq) ____nacl (aq) + ____co2 (g) + ____h2o (l)\n10. ____c3h5oh (l) + ____o2 (g) ____co2 (g) + ____h2o (g)\n11. ____nh3 (g) + ____cuo (s) ____n2 (g) + ____cu (s) + ____h2o (g)\n12. ____cu (s) + ____agno3 (aq) ____ag (s) + ____cu(no3)2 (aq)\n13. ____c12h22o11 (s) + ____o2 (g) ____co2 (g) + ____h2o (g)\n14. ____feo (s) + ____o2 (g) ____fe2o3 (s)\n15. ____cs2 (l) + ____nh3 (g) ____h2s (g) + ____nh4scn (s)\n16. ____naoh (aq) + ____hno3 (aq) ____nano3 (aq) + ____h2o (l)
Answer
Explanation:
Step1: Balance equation 1
Balance the number of atoms on both sides. For the reaction $\text{Al}(s)+\text{HCl}(aq)\rightarrow\text{AlCl}_3(aq)+\text{H}_2(g)$, we get $2\text{Al}(s) + 6\text{HCl}(aq)=2\text{AlCl}_3(aq)+3\text{H}_2(g)$
Step2: Balance equation 2
For $\text{K}(s)+\text{H}_2\text{O}(l)\rightarrow\text{KOH}(aq)+\text{H}_2(g)$, we have $2\text{K}(s)+2\text{H}_2\text{O}(l)=2\text{KOH}(aq)+\text{H}_2(g)$
Step3: Balance equation 3
For $\text{Mg}(s)+\text{N}_2(g)\rightarrow\text{Mg}_3\text{N}_2(s)$, it is $3\text{Mg}(s)+\text{N}_2(g)=\text{Mg}_3\text{N}_2(s)$
Step4: Balance equation 4
For $\text{NaNO}_3(s)\rightarrow\text{NaNO}_2(s)+\text{O}_2(g)$, we get $2\text{NaNO}_3(s)=2\text{NaNO}_2(s)+\text{O}_2(g)$
Step5: Balance equation 5
For $\text{Ca(OH)}_2(s)+\text{H}_3\text{PO}_4(aq)\rightarrow\text{Ca}_3(\text{PO}_4)_2(s)+\text{H}_2\text{O}(l)$, we have $3\text{Ca(OH)}_2(s)+2\text{H}_3\text{PO}_4(aq)=\text{Ca}_3(\text{PO}_4)_2(s)+6\text{H}_2\text{O}(l)$
Step6: Balance equation 6
For $\text{C}_3\text{H}_8(g)+\text{O}_2(g)\rightarrow\text{CO}_2(g)+\text{H}_2\text{O}(g)$, we get $\text{C}_3\text{H}_8(g)+5\text{O}_2(g)=3\text{CO}_2(g)+4\text{H}_2\text{O}(g)$
Step7: Balance equation 7
For $\text{NH}_3(g)+\text{O}_2(g)\rightarrow\text{NO}(g)+\text{H}_2(g)$, we have $4\text{NH}_3(g)+5\text{O}_2(g)=4\text{NO}(g)+6\text{H}_2(g)$
Step8: Balance equation 8
For $\text{N}_2(g)+\text{H}_2(g)\rightarrow\text{NH}_3(g)$, we get $\text{N}_2(g)+3\text{H}_2(g)=2\text{NH}_3(g)$
Step9: Balance equation 9
For $\text{Na}_2\text{CO}_3(s)+\text{HCl}(aq)\rightarrow\text{NaCl}(aq)+\text{CO}_2(g)+\text{H}_2\text{O}(l)$, we have $\text{Na}_2\text{CO}_3(s)+2\text{HCl}(aq)=2\text{NaCl}(aq)+\text{CO}_2(g)+\text{H}_2\text{O}(l)$
Step10: Balance equation 10
For $\text{C}_3\text{H}_5\text{OH}(l)+\text{O}_2(g)\rightarrow\text{CO}_2(g)+\text{H}_2\text{O}(g)$, we get $\text{C}_3\text{H}_5\text{OH}(l)+9\text{O}_2(g)=6\text{CO}_2(g)+8\text{H}_2\text{O}(g)$
Step11: Balance equation 11
For $\text{NH}_3(g)+\text{CuO}(s)\rightarrow\text{N}_2(g)+\text{Cu}(s)+\text{H}_2\text{O}(g)$, we have $2\text{NH}_3(g)+3\text{CuO}(s)=\text{N}_2(g)+3\text{Cu}(s)+3\text{H}_2\text{O}(g)$
Step12: Balance equation 12
For $\text{Cu}(s)+\text{AgNO}_3(aq)\rightarrow\text{Ag}(s)+\text{Cu(NO}_3)_2(aq)$, we get $\text{Cu}(s)+2\text{AgNO}_3(aq)=2\text{Ag}(s)+\text{Cu(NO}_3)_2(aq)$
Step13: Balance equation 13
For $\text{C}{12}\text{H}{22}\text{O}_{11}(s)+\text{O}2(g)\rightarrow\text{CO}2(g)+\text{H}2\text{O}(g)$, we get $\text{C}{12}\text{H}{22}\text{O}{11}(s)+12\text{O}_2(g)=12\text{CO}_2(g)+11\text{H}_2\text{O}(g)$
Step14: Balance equation 14
For $\text{FeO}(s)+\text{O}_2(g)\rightarrow\text{Fe}_2\text{O}_3(s)$, we get $4\text{FeO}(s)+\text{O}_2(g)=2\text{Fe}_2\text{O}_3(s)$
Step15: Balance equation 15
For $\text{CS}_2(l)+\text{NH}_3(g)\rightarrow\text{H}_2\text{S}(g)+\text{NH}_4\text{SCN}(s)$, we get $\text{CS}_2(l)+2\text{NH}_3(g)=\text{H}_2\text{S}(g)+\text{NH}_4\text{SCN}(s)$
Step16: Balance equation 16
For $\text{NaOH}(aq)+\text{HNO}_3(aq)\rightarrow\text{NaNO}_3(aq)+\text{H}_2\text{O}(l)$, we get $\text{NaOH}(aq)+\text{HNO}_3(aq)=\text{NaNO}_3(aq)+\text{H}_2\text{O}(l)$
Answer:
- $2\text{Al}(s) + 6\text{HCl}(aq)=2\text{AlCl}_3(aq)+3\text{H}_2(g)$
- $2\text{K}(s)+2\text{H}_2\text{O}(l)=2\text{KOH}(aq)+\text{H}_2(g)$
- $3\text{Mg}(s)+\text{N}_2(g)=\text{Mg}_3\text{N}_2(s)$
- $2\text{NaNO}_3(s)=2\text{NaNO}_2(s)+\text{O}_2(g)$
- $3\text{Ca(OH)}_2(s)+2\text{H}_3\text{PO}_4(aq)=\text{Ca}_3(\text{PO}_4)_2(s)+6\text{H}_2\text{O}(l)$
- $\text{C}_3\text{H}_8(g)+5\text{O}_2(g)=3\text{CO}_2(g)+4\text{H}_2\text{O}(g)$
- $4\text{NH}_3(g)+5\text{O}_2(g)=4\text{NO}(g)+6\text{H}_2(g)$
- $\text{N}_2(g)+3\text{H}_2(g)=2\text{NH}_3(g)$
- $\text{Na}_2\text{CO}_3(s)+2\text{HCl}(aq)=2\text{NaCl}(aq)+\text{CO}_2(g)+\text{H}_2\text{O}(l)$
- $\text{C}_3\text{H}_5\text{OH}(l)+9\text{O}_2(g)=6\text{CO}_2(g)+8\text{H}_2\text{O}(g)$
- $2\text{NH}_3(g)+3\text{CuO}(s)=\text{N}_2(g)+3\text{Cu}(s)+3\text{H}_2\text{O}(g)$
- $\text{Cu}(s)+2\text{AgNO}_3(aq)=2\text{Ag}(s)+\text{Cu(NO}_3)_2(aq)$
- $\text{C}{12}\text{H}{22}\text{O}_{11}(s)+12\text{O}_2(g)=12\text{CO}_2(g)+11\text{H}_2\text{O}(g)$
- $4\text{FeO}(s)+\text{O}_2(g)=2\text{Fe}_2\text{O}_3(s)$
- $\text{CS}_2(l)+2\text{NH}_3(g)=\text{H}_2\text{S}(g)+\text{NH}_4\text{SCN}(s)$
- $\text{NaOH}(aq)+\text{HNO}_3(aq)=\text{NaNO}_3(aq)+\text{H}_2\text{O}(l)$