a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. which equation should…

a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. which equation should you use to find the final number of moles of gas in the balloon after the deflation? $v_2=\frac{v_1n_2}{n_1}$ $n_2=\frac{v_2n_1}{v_1}$ $n_2=\frac{v_1n_1}{v_2}$ complete what is the final number of moles? 0.080 mol 0.80 mol 2 mol 12.5 mol

a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. which equation should you use to find the final number of moles of gas in the balloon after the deflation? $v_2=\frac{v_1n_2}{n_1}$ $n_2=\frac{v_2n_1}{v_1}$ $n_2=\frac{v_1n_1}{v_2}$ complete what is the final number of moles? 0.080 mol 0.80 mol 2 mol 12.5 mol

Answer

Explanation:

Step1: Identify given values

$V_1 = 5.0\ L$, $n_1=0.40\ mol$, $V_2 = 1.0\ L$

Step2: Use the correct formula

We use $n_2=\frac{V_2n_1}{V_1}$. Substitute the values: $n_2=\frac{1.0\ L\times0.40\ mol}{5.0\ L}$

Step3: Calculate the result

$n_2=\frac{0.40}{5.0}= 0.080\ mol$

Answer:

$0.080\ mol$