a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. which equation should…

a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. which equation should you use to find the final number of moles of gas in the balloon after the deflation?\n$v_2=\frac{v_1n_2}{n_1}$\n$n_2=\frac{v_2n_1}{v_1}$\n$n_2=\frac{v_1n_1}{v_2}$\ndone

a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. which equation should you use to find the final number of moles of gas in the balloon after the deflation?\n$v_2=\frac{v_1n_2}{n_1}$\n$n_2=\frac{v_2n_1}{v_1}$\n$n_2=\frac{v_1n_1}{v_2}$\ndone

Answer

Explanation:

Step1: Recall Avogadro's law

Avogadro's law states that at constant temperature and pressure, $\frac{V_1}{n_1}=\frac{V_2}{n_2}$, where $V_1$ and $n_1$ are the initial volume and number of moles, and $V_2$ and $n_2$ are the final volume and number of moles.

Step2: Rearrange the formula for $n_2$

Starting from $\frac{V_1}{n_1}=\frac{V_2}{n_2}$, cross - multiply to get $V_1n_2 = V_2n_1$. Then solve for $n_2$: $n_2=\frac{V_2n_1}{V_1}$.

Answer:

$n_2=\frac{V_2n_1}{V_1}$ (the second option)