5) i have a balloon that can hold 100 liters of air. if i blow up this balloon with 3 moles of oxygen gas at…

5) i have a balloon that can hold 100 liters of air. if i blow up this balloon with 3 moles of oxygen gas at a pressure of 1 atmosphere, what is the temperature of the balloon?
Answer
Explanation:
Step1: Recall ideal - gas law
The ideal - gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal - gas constant ($R=0.0821\ L\cdot atm/(mol\cdot K)$), and $T$ is temperature.
Step2: Rearrange the formula for temperature
We want to find $T$, so we can rewrite the ideal - gas law as $T=\frac{PV}{nR}$.
Step3: Substitute the given values
We know that $P = 1\ atm$, $V = 100\ L$, $n = 3\ mol$, and $R=0.0821\ L\cdot atm/(mol\cdot K)$. $T=\frac{1\ atm\times100\ L}{3\ mol\times0.0821\ L\cdot atm/(mol\cdot K)}$
Step4: Calculate the temperature
$T=\frac{100}{3\times0.0821}\ K\approx406\ K$
Answer:
$406\ K$