based on the activity series provided, which reactants will form products? f>cl>br>i\ncui2 + br2 →\ncl2 +…
based on the activity series provided, which reactants will form products? f>cl>br>i\ncui2 + br2 →\ncl2 + alf3 →\nbr2 + nacl →\ncuf2 + i2 →
Answer
Answer:
CuI2 + Br2 →
Explanation:
Step1: Understand activity series
The more reactive halogen can displace the less reactive one.
Step2: Analyze each option
- For CuI2 + Br2 →: Bromine (Br) is more reactive than iodine (I) according to F > Cl > Br > I. So Br2 can displace I - from CuI2 to form products.
- For Cl2 + AlF3 →: Fluorine (F) is more reactive than chlorine (Cl), so Cl2 cannot displace F - from AlF3.
- For Br2 + NaCl →: Chlorine (Cl) is more reactive than bromine (Br), so Br2 cannot displace Cl - from NaCl.
- For CuF2 + I2 →: Fluorine (F) is more reactive than iodine (I), so I2 cannot displace F - from CuF2.