a beaker contain 5 moles of koh will have of many grams of koh? 1mole koh= 56.11gkoh solving strategy: given…

a beaker contain 5 moles of koh will have of many grams of koh? 1mole koh= 56.11gkoh solving strategy: given × conversion factor 1 × conversion factor 2... = calculated answer 5molekoh 1molekoh 56.11gkoh 280.55gkoh

a beaker contain 5 moles of koh will have of many grams of koh? 1mole koh= 56.11gkoh solving strategy: given × conversion factor 1 × conversion factor 2... = calculated answer 5molekoh 1molekoh 56.11gkoh 280.55gkoh

Answer

Explanation:

Step1: Identify given and conversion factor

Given 5 moles of KOH, conversion factor is 56.11 g KOH per 1 mole KOH. $5\ \text{moles KOH}\times\frac{56.11\ \text{g KOH}}{1\ \text{mole KOH}}$

Step2: Perform calculation

$5\times56.11 = 280.55$

Answer:

280.55 g KOH