which best describes the reducing agent in the reaction below? cl₂(aq) + 2br⁻(aq) → 2cl⁻(aq) + br₂(aq)\no…

which best describes the reducing agent in the reaction below? cl₂(aq) + 2br⁻(aq) → 2cl⁻(aq) + br₂(aq)\no bromine (br) loses an electron, so it is the reducing agent.\no bromine (br) gains an electron, so it is the reducing agent.\no chlorine (cl) loses an electron, so it is the reducing agent.\no chlorine (cl) gains an electron, so it is the reducing agent.
Answer
Brief Explanations:
A reducing agent is oxidized in a redox - reaction, which means it loses electrons. In the reaction $\mathrm{Cl}{2}(aq)+2\mathrm{Br}^{-}(aq)\longrightarrow2\mathrm{Cl}^{-}(aq)+\mathrm{Br}{2}(aq)$, bromine goes from $\mathrm{Br}^{-}$ (oxidation state - 1) to $\mathrm{Br}{2}$ (oxidation state 0), indicating it loses electrons. Chlorine goes from $\mathrm{Cl}{2}$ (oxidation state 0) to $\mathrm{Cl}^{-}$ (oxidation state - 1), indicating it gains electrons. So, bromine is the reducing agent as it loses an electron.
Answer:
Bromine (Br) loses an electron, so it is the reducing agent.