what is the bond order for no₂⁻? 1 1.5 1.33 2 1.67 nitrogen is the central atom in each ion. count the total…

what is the bond order for no₂⁻? 1 1.5 1.33 2 1.67 nitrogen is the central atom in each ion. count the total number of valence electrons in each ion. n has 5 valence electrons. o has 6 valence electrons. thus, no₃⁻ should have 5 + 3(6) + 1 = 24 electrons in its structure; no₂⁻ should have 5 + 2(6) + 1 = 18 electrons in its structure; and no₂ should have 5 + 2(6) - 1 = 16 electrons in its structure. keep track of the total number of electrons in each structure as you add bonds and lone pairs. each single bond adds two electrons. each double bond adds four electrons. each lone pair adds two electrons. finally, check that each atom has an octet.

what is the bond order for no₂⁻? 1 1.5 1.33 2 1.67 nitrogen is the central atom in each ion. count the total number of valence electrons in each ion. n has 5 valence electrons. o has 6 valence electrons. thus, no₃⁻ should have 5 + 3(6) + 1 = 24 electrons in its structure; no₂⁻ should have 5 + 2(6) + 1 = 18 electrons in its structure; and no₂ should have 5 + 2(6) - 1 = 16 electrons in its structure. keep track of the total number of electrons in each structure as you add bonds and lone pairs. each single bond adds two electrons. each double bond adds four electrons. each lone pair adds two electrons. finally, check that each atom has an octet.

Answer

Explanation:

Step1: Determine resonance structures

$NO_2^-$ has two resonance - contributing structures. In one structure, there is a single bond between $N$ and one $O$ and a double bond between $N$ and the other $O$. In the resonance - hybrid structure, the bond order is calculated considering the resonance.

Step2: Calculate bond order formula

The formula for bond order in a molecule with resonance is $\text{Bond Order}=\frac{\text{Total number of bonds}}{\text{Number of equivalent bonds}}$. In $NO_2^-$, the total number of bonds between $N$ and $O$ atoms in the resonance - hybrid is equivalent to 3 (counting the partial double - bond character in the resonance hybrid), and the number of $N - O$ bonds is 2.

Step3: Calculate bond order

$\text{Bond Order}=\frac{3}{2}=1.5$

Answer:

1.5