the boron atom of bbr₃ has\none atomic orbital.\ntwo atomic orbitals.\nthree hybrid orbitals.\nfour hybrid…

Answer:

C. three hybrid orbitals.

Brief Explanations:

Boron in $BBr_3$ has 3 valence - electrons. It forms 3 sigma bonds with bromine atoms and has no lone pairs. Using the concept of hybridization, with steric number = 3 (3 bonding pairs), the hybridization is $sp^2$, resulting in three $sp^2$ hybrid orbitals.