c4h10 + o2 → ?co2 + h2o\nreactants products\n4 c 1\n10 h 2\n2 o 3\nnow we want to start balancing the…
c4h10 + o2 → ?co2 + h2o\nreactants products\n4 c 1\n10 h 2\n2 o 3\nnow we want to start balancing the equation. there are currently 4 carbon atoms on the left. what coefficient could we use in front of co2 to get 4 carbon atoms on the right?
Answer
Explanation:
Step1: Analyze carbon - atom balance
We know that the left - hand side of the chemical equation has 4 carbon atoms in $C_4H_{10}$. In $CO_2$, each molecule has 1 carbon atom.
Step2: Determine the coefficient
To have 4 carbon atoms on the right - hand side (in $CO_2$), if we let the coefficient of $CO_2$ be $x$, and since each $CO_2$ has 1 carbon atom, we need $x\times1 = 4$. So $x = 4$.
Answer:
4