caco₃(s) $xrightarrow{delta}$ cao(s) + co₂(g)\n3.25 mol caco₃ decomposes according to the reaction…

caco₃(s) $xrightarrow{delta}$ cao(s) + co₂(g)\n3.25 mol caco₃ decomposes according to the reaction above.\nwhat volume of co₂ gas is produced once the gas cools to stp?\n? l co₂

caco₃(s) $xrightarrow{delta}$ cao(s) + co₂(g)\n3.25 mol caco₃ decomposes according to the reaction above.\nwhat volume of co₂ gas is produced once the gas cools to stp?\n? l co₂

Answer

Explanation:

Step1: Determine mole - ratio

From the balanced equation $CaCO_3(s)\xrightarrow{\Delta}CaO(s)+CO_2(g)$, the mole - ratio of $CaCO_3$ to $CO_2$ is 1:1. So, if 3.25 mol of $CaCO_3$ decomposes, 3.25 mol of $CO_2$ is produced.

Step2: Use molar volume at STP

At standard temperature and pressure (STP), the molar volume of any ideal gas is $V_m = 22.4\ L/mol$. The volume $V$ of a gas is given by the formula $V=n\times V_m$, where $n$ is the number of moles of the gas. Substitute $n = 3.25\ mol$ and $V_m=22.4\ L/mol$ into the formula: $V = 3.25\ mol\times22.4\ L/mol$. $V=72.8\ L$

Answer:

72.8