caco₃(s) $xrightarrow{delta}$ cao(s) + co₂(g)\nwhat volume of co₂ gas is produced when 2.00 mol caco₃…

caco₃(s) $xrightarrow{delta}$ cao(s) + co₂(g)\nwhat volume of co₂ gas is produced when 2.00 mol caco₃ decomposes at stp?\n? l co₂
Answer
Explanation:
Step1: Determine mole - ratio
From the balanced chemical equation $CaCO_3(s)\xrightarrow{\Delta}CaO(s)+CO_2(g)$, the mole - ratio of $CaCO_3$ to $CO_2$ is 1:1. So, 2.00 mol of $CaCO_3$ will produce 2.00 mol of $CO_2$.
Step2: Use molar volume at STP
At STP (Standard Temperature and Pressure, 0°C and 1 atm), the molar volume of any ideal gas is 22.4 L/mol. The volume $V$ of $CO_2$ is given by the formula $V = n\times V_m$, where $n$ is the number of moles and $V_m$ is the molar volume. Substitute $n = 2.00$ mol and $V_m=22.4$ L/mol into the formula: $V=2.00\ mol\times22.4\ L/mol$. $V = 44.8$ L.
Answer:
44.8