calcium bicarbonate (ca(hco₃)₂)\nca:h:c:o = 1:2:2\nlithium sulfide (li₂s)\nli:s = 2:
calcium bicarbonate (ca(hco₃)₂)\nca:h:c:o = 1:2:2\nlithium sulfide (li₂s)\nli:s = 2:
Answer
Explanation:
Step1: Analyze calcium bicarbonate
In $Ca(HCO_3)_2$, there are 1 calcium (Ca) atom, 2 hydrogen (H) atoms, 2 carbon (C) atoms and 6 oxygen (O) atoms. So the ratio $Ca:H:C:O = 1:2:2:6$. The missing number for calcium bicarbonate is 6.
Step2: Analyze lithium sulfide
In $Li_2S$, there are 2 lithium (Li) atoms and 1 sulfur (S) atom. So the ratio $Li:S=2:1$. The missing number for lithium sulfide is 1.
Answer:
6 1