calcium carbonate (caco₃) is an important component of coral reefs. how many moles are in 98.6 g of caco₃…

calcium carbonate (caco₃) is an important component of coral reefs. how many moles are in 98.6 g of caco₃? type in your answer using the correct number of significant figures. 98.6 g caco₃ = mol caco₃ done
Answer
Explanation:
Step1: Calculate molar mass of $CaCO_3$
The molar mass of $Ca$ is approximately $40.08\ g/mol$, $C$ is $12.01\ g/mol$ and $O$ is $16.00\ g/mol$. For $CaCO_3$, molar mass $M=(40.08 + 12.01+3\times16.00)\ g/mol=100.09\ g/mol$.
Step2: Use the formula $n=\frac{m}{M}$
where $n$ is the number of moles, $m$ is the mass and $M$ is the molar mass. Given $m = 98.6\ g$ and $M=100.09\ g/mol$, then $n=\frac{98.6\ g}{100.09\ g/mol}\approx0.985\ mol$.
Answer:
$0.985$