calculate the number of moles in 75.0 g of dinitrogen trioxide (n₂o₃).\n0.987 mol\n1.24 mol\n1.63 mol\n1.70…

calculate the number of moles in 75.0 g of dinitrogen trioxide (n₂o₃).\n0.987 mol\n1.24 mol\n1.63 mol\n1.70 mol

calculate the number of moles in 75.0 g of dinitrogen trioxide (n₂o₃).\n0.987 mol\n1.24 mol\n1.63 mol\n1.70 mol

Answer

Explanation:

Step1: Calculate molar mass of N₂O₃

The molar mass of N is 14.01 g/mol and of O is 16.00 g/mol. For N₂O₃, molar mass $M=(2\times14.01 + 3\times16.00)$ g/mol$=76.02$ g/mol.

Step2: Use mole - mass formula

The formula to calculate the number of moles $n$ is $n=\frac{m}{M}$, where $m = 75.0$ g and $M = 76.02$ g/mol. So $n=\frac{75.0}{76.02}\approx0.987$ mol.

Answer:

0.987 mol