calculate the number of moles in 75.0 g of dinitrogen trioxide (n2o3). 0.987 mol 1.24 mol 1.63 mol 1.70 mol…

calculate the number of moles in 75.0 g of dinitrogen trioxide (n2o3). 0.987 mol 1.24 mol 1.63 mol 1.70 mol done

calculate the number of moles in 75.0 g of dinitrogen trioxide (n2o3). 0.987 mol 1.24 mol 1.63 mol 1.70 mol done

Answer

Explanation:

Step1: Calculate molar mass of $N_2O_3$

The molar mass of nitrogen ($N$) is approximately $14.01\ g/mol$ and oxygen ($O$) is approximately $16.00\ g/mol$. For $N_2O_3$, $M=(2\times14.01)+(3\times16.00)=76.02\ g/mol$.

Step2: Calculate number of moles

The formula for number of moles $n=\frac{m}{M}$, where $m = 75.0\ g$ and $M = 76.02\ g/mol$. So $n=\frac{75.0}{76.02}\approx0.987\ mol$.

Answer:

0.987 mol