calculate the percentage by mass, of carbon in albuterol, c₁₃h₂₁no₃. given carbon is 12.0 g/mol, hydrogen is…

calculate the percentage by mass, of carbon in albuterol, c₁₃h₂₁no₃. given carbon is 12.0 g/mol, hydrogen is 1.0 g/mol, nitrogen is 14.0 g/mol, and oxygen is 16 g/mol.\na 65.3%\nb 34.2%\nc 0.34\nd 50.2%\ne none of the above

calculate the percentage by mass, of carbon in albuterol, c₁₃h₂₁no₃. given carbon is 12.0 g/mol, hydrogen is 1.0 g/mol, nitrogen is 14.0 g/mol, and oxygen is 16 g/mol.\na 65.3%\nb 34.2%\nc 0.34\nd 50.2%\ne none of the above

Answer

Explanation:

Step1: Calculate molar mass of albuterol

$M = 13\times12.0+21\times1.0 + 14.0+3\times16$ $M=156 + 21+14 + 48$ $M = 239\ g/mol$

Step2: Calculate mass of carbon in albuterol

Mass of carbon $=13\times12.0 = 156\ g/mol$

Step3: Calculate mass - percentage of carbon

Mass - percentage of carbon $=\frac{156}{239}\times100%$ $=\frac{15600}{239}% \approx 65.3%$

Answer:

A. 65.3%