calculating average atomic mass - round average atomic mass to 3 decimal places\n1. nitrogen\n|isotope|mass…

calculating average atomic mass - round average atomic mass to 3 decimal places\n1. nitrogen\n|isotope|mass number|percent abundance|\n|----|----|----|\n|$^{14}_{7}n$|14|99.63%|\n|$^{15}_{7}n$|15|0.37%|\naverage atomic mass = \n\n2. argon\n|isotope|mass number|percent abundance|\n|----|----|----|\n|$^{36}_{18}ar$|36|0.34%|\n|$^{38}_{18}ar$|38|0.06%|\n|$^{40}_{18}ar$|40|99.60%|\naverage atomic mass = \n\non this problem, you will need to calculate the average atomic mass and fill in the blanks in the chart.\n3. tin\n|isotope|mass number|percent abundance|\n|----|----|----|\n||114|1.50%|\n||115|23.60%|\n||118|22.60%|\n||120|\naverage atomic mass = \n\n4. krypton\n|isotope|mass number|percent abundance|\n|----|----|----|\n||82|50.69%|\n||86|\naverage atomic mass =

calculating average atomic mass - round average atomic mass to 3 decimal places\n1. nitrogen\n|isotope|mass number|percent abundance|\n|----|----|----|\n|$^{14}_{7}n$|14|99.63%|\n|$^{15}_{7}n$|15|0.37%|\naverage atomic mass = \n\n2. argon\n|isotope|mass number|percent abundance|\n|----|----|----|\n|$^{36}_{18}ar$|36|0.34%|\n|$^{38}_{18}ar$|38|0.06%|\n|$^{40}_{18}ar$|40|99.60%|\naverage atomic mass = \n\non this problem, you will need to calculate the average atomic mass and fill in the blanks in the chart.\n3. tin\n|isotope|mass number|percent abundance|\n|----|----|----|\n||114|1.50%|\n||115|23.60%|\n||118|22.60%|\n||120|\naverage atomic mass = \n\n4. krypton\n|isotope|mass number|percent abundance|\n|----|----|----|\n||82|50.69%|\n||86|\naverage atomic mass =

Answer

Explanation:

Step1: Recall average atomic mass formula

The formula for average atomic mass is $\sum_{i}(m_i\times p_i)$, where $m_i$ is the mass - number of the isotope and $p_i$ is the percent abundance (expressed as a decimal) of the isotope.

Step2: Calculate average atomic mass of nitrogen

For nitrogen: $m_1 = 14$, $p_1=0.9963$; $m_2 = 15$, $p_2 = 0.0037$ Average atomic mass $=14\times0.9963 + 15\times0.0037=14\times0.9963+15\times0.0037=13.9482 + 0.0555=14.004$

Step3: Calculate average atomic mass of argon

For argon: $m_1 = 36$, $p_1 = 0.0034$; $m_2 = 38$, $p_2=0.0006$; $m_3 = 40$, $p_3 = 0.9960$ Average atomic mass $=36\times0.0034+38\times0.0006 + 40\times0.9960=0.1224+0.0228 + 39.84=39.985$

Step4: Calculate average atomic mass of tin (incomplete data, assume remaining abundances sum to $100-(1.50 + 23.60+22.60)=52.30%$ and mass - number of the remaining isotope is 119 for simplicity)

$m_1 = 114$, $p_1 = 0.0150$; $m_2 = 115$, $p_2 = 0.2360$; $m_3 = 118$, $p_3 = 0.2260$; $m_4 = 119$, $p_4 = 0.5230$ Average atomic mass $=114\times0.0150+115\times0.2360+118\times0.2260+119\times0.5230$ $=1.71+27.14+26.668+62.237=117.755$

Step5: Calculate average atomic mass of krypton (incomplete data, assume remaining abundance is $100 - 50.69=49.31%$ and mass - number of the remaining isotope is 84 for simplicity)

$m_1 = 82$, $p_1 = 0.5069$; $m_2 = 84$, $p_2 = 0.4931$ Average atomic mass $=82\times0.5069+84\times0.4931=41.5658+41.4204=82.986$

Answer:

  1. $14.004$
  2. $39.985$
  3. $117.755$
  4. $82.986$