carl makes the table below to determine the number of atoms of each element in the chemical formula…

carl makes the table below to determine the number of atoms of each element in the chemical formula 4ca(clo₃)₂. what mistake did carl make? element calculation total atoms calcium 1×4 4 chlorine 1×2 2 oxygen 3×2 6 he did not multiply the calcium atoms by the subscript 2. he did not add the coefficient 4 to the chlorine and oxygen atoms. he did not add the subscript 2 to the calcium atoms. he did not multiply the chlorine and oxygen atoms by the coefficient 4.

carl makes the table below to determine the number of atoms of each element in the chemical formula 4ca(clo₃)₂. what mistake did carl make? element calculation total atoms calcium 1×4 4 chlorine 1×2 2 oxygen 3×2 6 he did not multiply the calcium atoms by the subscript 2. he did not add the coefficient 4 to the chlorine and oxygen atoms. he did not add the subscript 2 to the calcium atoms. he did not multiply the chlorine and oxygen atoms by the coefficient 4.

Answer

Answer:

He did not multiply the chlorine and oxygen atoms by the coefficient 4.

Explanation:

Step1: Analyze chemical formula

The formula is $4Ca(ClO_3)_2$.

Step2: Determine atom - counting rule

For a compound $aX_bY_c$, the number of $X$ atoms is $a\times b$ and of $Y$ atoms is $a\times c$.

Step3: Check Carl's work

For chlorine and oxygen in $4Ca(ClO_3)_2$, Carl only considered the sub - script inside the parentheses and not the coefficient 4 outside. He should have multiplied the number of chlorine and oxygen atoms by 4. The correct number of chlorine atoms is $1\times2\times4 = 8$ and of oxygen atoms is $3\times2\times4=24$.