a certain radionuclide is used to diagnose lymphoma. an atom of this radionuclide contains 31 protons and 36…

a certain radionuclide is used to diagnose lymphoma. an atom of this radionuclide contains 31 protons and 36 neutrons. which statement is correct about the radionuclide?\nthe atomic number is 31, the mass number is 67, and its symbol is $_{31}^{67}ga$.\nthe atomic number is 31, the mass number is 67, and its symbol is $_{67}^{31}ga$.\nthe atomic number is 67, the mass number is 31, and its symbol is $_{31}^{67}ga$.\nthe atomic number is 67, the mass number is 31, and its symbol is $_{67}^{31}ga$.

a certain radionuclide is used to diagnose lymphoma. an atom of this radionuclide contains 31 protons and 36 neutrons. which statement is correct about the radionuclide?\nthe atomic number is 31, the mass number is 67, and its symbol is $_{31}^{67}ga$.\nthe atomic number is 31, the mass number is 67, and its symbol is $_{67}^{31}ga$.\nthe atomic number is 67, the mass number is 31, and its symbol is $_{31}^{67}ga$.\nthe atomic number is 67, the mass number is 31, and its symbol is $_{67}^{31}ga$.

Answer

Explanation:

Step1: Recall atomic number definition

The atomic number ($Z$) is equal to the number of protons. Given 31 protons, so $Z = 31$.

Step2: Calculate mass number

The mass number ($A$) is the sum of protons and neutrons. $A=31 + 36=67$.

Step3: Determine element symbol format

The symbol of an element is written as ${Z}^{A}\text{X}$, where $\text{X}$ is the chemical - symbol of the element. Gallium has the symbol $\text{Ga}$, and with $Z = 31$ and $A = 67$, the symbol is ${31}^{67}\text{Ga}$.

Answer:

The atomic number is 31, the mass number is 67, and its symbol is $_{31}^{67}\text{Ga}$.