ch.2 worksheet #2: {30pts} density problems\nanswer the following density problems. show your work on…
ch.2 worksheet #2: {30pts} density problems\nanswer the following density problems. show your work on separate paper.\n1) calculate the density of a liquid 17.45ml of which weighs 16.3g.\n2) calculate the density of carbon dioxide gas, given that 450ml weighs .891g.\n3) what is the density of ether (which used to be used as an anesthetic) given that 300.0ml weighs 217.5g?\n4) given that 140ml of chlorine gas weighs .450g; find the density of chlorine in g/l.\n5) whats the density (in g/ml) of 15.0l of liposuctioned body fat weighing 13.77kg?\n6) a solid plastic block is 13.75hg and takes up 148dm³. whats its density (in g/ml)?\n7) a window has a volume of 2035cm³ and mass of 6.7kg. whats its density (in g/ml)?\n8) how many ml are there in 500.0g of mercury, given that the density of mercury is 13.6g/ml?\n9) how many grams of glycerin (used as a skin moisturizer), density 1.25g/ml, will a 125ml flask hold?\n10) mercury has a density of 13.69g/ml. what is the volume of 1.2kg of it?\n11) a rock has a density of 6.3g/ml. whats the mass of a 580cm³ rock?\n12) what would be the volume of 325kg of iron, given that irons density is 7.9g/ml?\n13) the human body has a density of 1.02 - 1.10. a small cube of cadaver tissue (measuring 1.50cm on a side) is taken and weighs 3.50g. what is the density of the tissue?\n14) whats the mass in grams of a block of silver measuring 2.50cm by 8.00cm by 4.00cm, given that the density of silver is 10.5g/cm³?\n15) calculate the mass of a block of an alloy measuring 3.62cm by 1.23m by 1.00cm, given that the density of the alloy is 9.63g/cm³.
Answer
Explanation:
Step1: Recall density formula
The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume.
Step2: Solve problem 1
Given $V = 17.45mL$ and $m=16.3g$. Then $\rho=\frac{16.3g}{17.45mL}\approx0.934g/mL$.
Step3: Solve problem 2
Given $V = 450mL$ and $m = 0.891g$. Then $\rho=\frac{0.891g}{450mL}=0.00198g/mL$.
Step4: Solve problem 3
Given $V = 300.0mL$ and $m = 217.5g$. Then $\rho=\frac{217.5g}{300.0mL}=0.725g/mL$.
Step5: Solve problem 4
First convert volume to liters: $V=140mL = 0.14L$, $m = 0.450g$. Then $\rho=\frac{0.450g}{0.14L}\approx3.21g/L$.
Step6: Solve problem 5
Given $V = 15.0L=15000mL$ and $m = 13.77kg = 13770g$. Then $\rho=\frac{13770g}{15000mL}=0.918g/mL$.
Step7: Solve problem 6
Given $m = 13.75kg=13750g$ and $V = 10480cm^{3}=10480mL$. Then $\rho=\frac{13750g}{10480mL}\approx1.31g/mL$.
Step8: Solve problem 7
Given $m = 6.7kg = 6700g$ and $V=2035cm^{3}=2035mL$. Then $\rho=\frac{6700g}{2035mL}\approx3.29g/mL$.
Step9: Solve problem 8
Given $\rho = 13.6g/mL$ and $m = 500.0g$. Using $V=\frac{m}{\rho}$, we have $V=\frac{500.0g}{13.6g/mL}\approx36.8mL$.
Step10: Solve problem 9
Given $\rho = 1.25g/mL$ and $V = 125mL$. Using $m=\rho V$, we have $m=1.25g/mL\times125mL = 156.25g$.
Step11: Solve problem 10
Given $\rho = 13.69g/mL$ and $m = 1.2kg=1200g$. Using $V=\frac{m}{\rho}$, we have $V=\frac{1200g}{13.69g/mL}\approx87.66mL$.
Step12: Solve problem 11
Given $\rho = 6.3g/mL$ and $V = 580cm^{3}=580mL$. Using $m=\rho V$, we have $m=6.3g/mL\times580mL = 3654g$.
Step13: Solve problem 12
Given $\rho = 7.9g/mL$ and $m = 325kg = 325000g$. Using $V=\frac{m}{\rho}$, we have $V=\frac{325000g}{7.9g/mL}\approx41139.24mL$.
Step14: Solve problem 13
Given $V=3.50cm\times2.50cm\times8.00cm = 70cm^{3}=70mL$, $\rho = 10.5g/cm^{3}=10.5g/mL$. Using $m=\rho V$, we have $m=10.5g/mL\times70mL = 735g$.
Step15: Solve problem 14
Given $V=3.62cm\times1.23cm\times1.00cm = 4.4526cm^{3}$, $\rho = 9.63g/cm^{[SSE Completed, Client Connection Error][LLM SSE On Failure]