the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh)…

the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh). co₂ + 2lioh → li₂co₃ + h₂o the molar mass co₂ is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co₂? 0.290 moles 0.579 moles 1.16 moles 1.73 moles

the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh). co₂ + 2lioh → li₂co₃ + h₂o the molar mass co₂ is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co₂? 0.290 moles 0.579 moles 1.16 moles 1.73 moles

Answer

Explanation:

Step1: Calculate moles of CO₂

Use the formula $n=\frac{m}{M}$, where $m$ is mass and $M$ is molar - mass. Given $m = 25.5$ g and $M = 44.01$ g/mol for $CO_2$. $n_{CO_2}=\frac{25.5}{44.01}\approx0.5794$ mol

Step2: Determine moles of LiOH from mole - ratio

From the balanced chemical equation $CO_2 + 2LiOH\rightarrow Li_2CO_3+H_2O$, the mole - ratio of $CO_2$ to $LiOH$ is $1:2$. So $n_{LiOH}=2\times n_{CO_2}$. $n_{LiOH}=2\times0.5794 = 1.1588\approx1.16$ mol

Answer:

1.16 moles