this is the chemical formula for zinc bromate...

# Explanation: ## Step1: Calculate molar mass of each element - Molar mass of \(Zn\): \(M_{Zn}=65.38\space g/mol\) - Molar mass of \(Br\): There are \(2\) \(Br\) atoms. \(M_{Br}=2\times79.904 = 159.808\space g/mol\) - Molar mass of \(O\): There are \(6\) \(O\) atoms. \(M_{O}=6\times16.00=96.00\space g/mol\) ## Step2: Calculate molar mass of \(Zn(BrO_{3})_{2}\) \(M = M_{Zn}+M_{Br}+M_{O}=65.38 + 159.808+96.00=321.188\space g/mol\) ## Step3: Calculate mass percent of \(O\) Mass percent formula: \(\text{Mass}\%=\frac{\text{Mass of component}}{\text{Total mass}}\times100\) \(\text{Mass}\%\text{ of }O=\frac{96.00}{321.188}\times 100\approx29.9\%\) # Answer: \(30\%\)