a chemist makes a solution of naoh for use in an experiment. she dissolves 0.00500 mol naoh in 1.00 l h2o…

a chemist makes a solution of naoh for use in an experiment. she dissolves 0.00500 mol naoh in 1.00 l h2o. the naoh completely dissociates to form a solution with oh-=0.00500 m. what is the poh of this solution? 0.00500 5.00 2.30 -2.30 done

a chemist makes a solution of naoh for use in an experiment. she dissolves 0.00500 mol naoh in 1.00 l h2o. the naoh completely dissociates to form a solution with oh-=0.00500 m. what is the poh of this solution? 0.00500 5.00 2.30 -2.30 done

Answer

Answer:

C. 2.30

Explanation:

Step1: Recall pOH formula

$pOH = -\log[OH^-]$

Step2: Substitute the given value

$pOH=-\log(0.00500)$

Step3: Calculate the result

$pOH = 2.30$