a chemist is using a solution of hno3 that has a ph of 3.75. what is oh- for the solution? round to the…

a chemist is using a solution of hno3 that has a ph of 3.75. what is oh- for the solution? round to the nearest hundredth. × 10^n m n = what is the poh of the solution? round to the nearest hundredth.

a chemist is using a solution of hno3 that has a ph of 3.75. what is oh- for the solution? round to the nearest hundredth. × 10^n m n = what is the poh of the solution? round to the nearest hundredth.

Answer

Answer:

  1. First, find pOH:
    • pOH = 10.25
  2. Then, find ([OH^-]):
    • ([OH^-]=5.62\times10^{-11}\text{ M}), (n = - 11)

Explanation:

Step1: Calculate pOH

We know that (pH + pOH=14). Given (pH = 3.75), then (pOH=14 - pH=14 - 3.75 = 10.25)

Step2: Calculate ([OH^-])

The formula for (pOH) is (pOH=-\log[OH^-]). Rearranging for ([OH^-]) gives ([OH^-]=10^{-pOH}). Substituting (pOH = 10.25) into the formula, ([OH^-]=10^{- 10.25}\approx5.62\times10^{-11}\text{ M}), so (n=-11)