chemistry\n1. if i have 12 l of a gas at 15 k and i expand it to a volume of 100.5 l what is the new…

chemistry\n1. if i have 12 l of a gas at 15 k and i expand it to a volume of 100.5 l what is the new temperature?

chemistry\n1. if i have 12 l of a gas at 15 k and i expand it to a volume of 100.5 l what is the new temperature?

Answer

Explanation:

Step1: Identify the gas - law formula

We use Charles's law $\frac{V_1}{T_1}=\frac{V_2}{T_2}$, where $V_1$ is the initial volume, $T_1$ is the initial temperature, $V_2$ is the final volume, and $T_2$ is the final temperature.

Step2: Rearrange the formula for $T_2$

$T_2=\frac{V_2T_1}{V_1}$

Step3: Substitute the given values

Given $V_1 = 12\ L$, $T_1=15\ K$, $V_2 = 100.5\ L$. Then $T_2=\frac{100.5\times15}{12}$.

Step4: Calculate the result

$T_2=\frac{1507.5}{12}=125.625\ K$

Answer:

$125.625\ K$