chemistry\n1. a gas at 300 k with a pressure of 1.5 atm and a volume of 3 l is compressed to a volume of 2 l…

Explanation:

Step1: Recall the combined gas law

The combined gas law is $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$.

Step2: Identify the given values

$P_1 = 1.5$ atm, $V_1=3$ L, $T_1 = 300$ K, $V_2 = 2$ L, $T_2=400$ K.

Step3: Rearrange the formula to solve for $P_2$

$P_2=\frac{P_1V_1T_2}{T_1V_2}$.

Step4: Substitute the values

$P_2=\frac{1.5\times3\times400}{300\times2}$. First, calculate the numerator: $1.5\times3\times400 = 1800$. Then, calculate the denominator: $300\times2=600$. So, $P_2=\frac{1800}{600}= 3$ atm.

Answer:

3 atm