chemistry: ions in chemical compounds\nname: micah carter\nhour: 7 date: 9/20/25\ncomplete the following…

chemistry: ions in chemical compounds\nname: micah carter\nhour: 7 date: 9/20/25\ncomplete the following table, being sure that the total charge on the resulting compound is zero.\n| ions | chloride cl⁻ | hydroxide oh⁻ | nitrate no₃⁻ | sulfate so₄²⁻ | sulfide s²⁻ | carbonate co₃²⁻ | phosphate po₄³⁻ |\n| ---- | ---- | ---- | ---- | ---- | ---- | ---- | ---- |\n| hydrogen h⁺ | hcl | hoh | hno₃ | | | | |\n| sodium na⁺ | nacl | naoh | nano₃ | | | | |\n| ammonium nh₄⁺ | nh₄cl | nh₄oh | nh₄no₃ | | | | |\n| potassium k⁺ | kcl | koh | kno₃ | | | | |\n| calcium ca²⁺ | cacl₂ | ca(oh)₂ | ca(no₃)₂ | | | | |\n| magnesium mg²⁺ | mgcl₂ | mg(oh)₂ | mg(no₃)₂ | | | | |\n| aluminum al³⁺ | alcl₃ | al(oh)₃ | al(no₃)₃ | | | | |\n| iron (ii) fe²⁺ | | | | | | | |\n| iron (iii) fe³⁺ | fecl₃ | fe(oh)₃ | | | | | |\n| copper (i) cu⁺ | cucl | cuoh | | | | | |

chemistry: ions in chemical compounds\nname: micah carter\nhour: 7 date: 9/20/25\ncomplete the following table, being sure that the total charge on the resulting compound is zero.\n| ions | chloride cl⁻ | hydroxide oh⁻ | nitrate no₃⁻ | sulfate so₄²⁻ | sulfide s²⁻ | carbonate co₃²⁻ | phosphate po₄³⁻ |\n| ---- | ---- | ---- | ---- | ---- | ---- | ---- | ---- |\n| hydrogen h⁺ | hcl | hoh | hno₃ | | | | |\n| sodium na⁺ | nacl | naoh | nano₃ | | | | |\n| ammonium nh₄⁺ | nh₄cl | nh₄oh | nh₄no₃ | | | | |\n| potassium k⁺ | kcl | koh | kno₃ | | | | |\n| calcium ca²⁺ | cacl₂ | ca(oh)₂ | ca(no₃)₂ | | | | |\n| magnesium mg²⁺ | mgcl₂ | mg(oh)₂ | mg(no₃)₂ | | | | |\n| aluminum al³⁺ | alcl₃ | al(oh)₃ | al(no₃)₃ | | | | |\n| iron (ii) fe²⁺ | | | | | | | |\n| iron (iii) fe³⁺ | fecl₃ | fe(oh)₃ | | | | | |\n| copper (i) cu⁺ | cucl | cuoh | | | | | |

Answer

Explanation:

Step1: Determine compound formulas

For each pair of cations and anions, balance the charges to form a neutral - charge compound. For example, when a calcium ion ($Ca^{2 + }$) combines with a sulfate ion ($SO_{4}^{2 - }$), the formula is $CaSO_{4}$ because the + 2 charge of calcium balances the - 2 charge of sulfate.

Step2: Write formulas systematically

Go through each row (cation) and column (anion) combination. For a hydrogen ion ($H^{+}$) and a carbonate ion ($CO_{3}^{2 - }$), two hydrogen ions are needed to balance the - 2 charge of the carbonate ion, so the formula is $H_{2}CO_{3}$.

Answer:

Ions Chloride $Cl^{-}$ Hydroxide $OH^{-}$ Nitrate $NO_{3}^{-}$ Sulfate $SO_{4}^{2 - }$ Sulfide $S^{2 - }$ Carbonate $CO_{3}^{2 - }$ Phosphate $PO_{4}^{3 - }$
Hydrogen $H^{+}$ $HCl$ $H_{2}O$ (Note: $HOH$ is incorrect, it's $H_{2}O$) $HNO_{3}$ $H_{2}SO_{4}$ $H_{2}S$ $H_{2}CO_{3}$ $H_{3}PO_{4}$
Sodium $Na^{+}$ $NaCl$ $NaOH$ $NaNO_{3}$ $Na_{2}SO_{4}$ $Na_{2}S$ $Na_{2}CO_{3}$ $Na_{3}PO_{4}$
Ammonium $NH_{4}^{+}$ $NH_{4}Cl$ $NH_{4}OH$ (usually written as $NH_{3}\cdot H_{2}O$) $NH_{4}NO_{3}$ $(NH_{4}){2}SO{4}$ $(NH_{4})_{2}S$ $(NH_{4}){2}CO{3}$ $(NH_{4}){3}PO{4}$
Potassium $K^{+}$ $KCl$ $KOH$ $KNO_{3}$ $K_{2}SO_{4}$ $K_{2}S$ $K_{2}CO_{3}$ $K_{3}PO_{4}$
Calcium $Ca^{2 + }$ $CaCl_{2}$ $Ca(OH)_{2}$ $Ca(NO_{3})_{2}$ $CaSO_{4}$ $CaS$ $CaCO_{3}$ $Ca_{3}(PO_{4})_{2}$
Magnesium $Mg^{2 + }$ $MgCl_{2}$ $Mg(OH)_{2}$ $Mg(NO_{3})_{2}$ $MgSO_{4}$ $MgS$ $MgCO_{3}$ $Mg_{3}(PO_{4})_{2}$
Aluminum $Al^{3 + }$ $AlCl_{3}$ $Al(OH)_{3}$ $Al(NO_{3})_{3}$ $Al_{2}(SO_{4})_{3}$ $Al_{2}S_{3}$ $Al_{2}(CO_{3})_{3}$ $AlPO_{4}$
Iron (II) $Fe^{2 + }$ $FeCl_{2}$ $Fe(OH)_{2}$ $Fe(NO_{3})_{2}$ $FeSO_{4}$ $FeS$ $FeCO_{3}$ $Fe_{3}(PO_{4})_{2}$
Iron (III) $Fe^{3 + }$ $FeCl_{3}$ $Fe(OH)_{3}$ $Fe(NO_{3})_{3}$ $Fe_{2}(SO_{4})_{3}$ $Fe_{2}S_{3}$ $Fe_{2}(CO_{3})_{3}$ $FePO_{4}$
Copper (I) $Cu^{+}$ $CuCl$ $CuOH$ (unstable, usually forms $Cu_{2}O$ and $H_{2}O$ in solution) $CuNO_{3}$ $Cu_{2}SO_{4}$ $Cu_{2}S$ $Cu_{2}CO_{3}$ $Cu_{3}PO_{4}$