8. a chemistry teacher needs to make 2.30 l of a potassium chloride solution for an experiment. the…

8. a chemistry teacher needs to make 2.30 l of a potassium chloride solution for an experiment. the concentration of the required solution is 3.10 m how many grams of kcl will she need to use? 7.13 g kcl 231 g kcl .0956 g kcl

8. a chemistry teacher needs to make 2.30 l of a potassium chloride solution for an experiment. the concentration of the required solution is 3.10 m how many grams of kcl will she need to use? 7.13 g kcl 231 g kcl .0956 g kcl

Answer

Explanation:

Step1: Calculate moles of KCl

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume. Given $M = 3.10\ M$ and $V=2.30\ L$. So $n=3.10\ mol/L\times2.30\ L = 7.13\ mol$.

Step2: Calculate mass of KCl

The molar - mass of KCl is $M_{KCl}=39.1\ g/mol + 35.45\ g/mol=74.55\ g/mol$. Use the formula $m=n\times M_{KCl}$. So $m = 7.13\ mol\times74.55\ g/mol\approx532\ g$.

Answer:

None of the provided options are correct. The correct mass of KCl is approximately 532 g.